1.52 atm 131.26 mL 1.52 atm

C9H11NO4 (9x12)+(11x1)+(14x1)+(16x4) = 197g/mol

a P1 T1 P2 T2 B C 3.25 atm 298 K 4.34 atm 398 K 550 mm Hg 273 K   P1 T1 P2 T2 a 3.25 atm 298 K 4.34 atm  398 K B 550 mm Hg 273 K 0.459 atm -100 oC C 0.5 atm 250 K 955 mm Hg 625 K 

113.538 L

b.  P1 V1 are both fine as is              T1, P2 and T2 both need to be converted. T1 and T2 simply add 273 to convert C to K, so T1 = 278 K and T2 = 323K for P2 1atm = 760mm Hg so 700mmHg x 1atm/760mmHg = 0.921atm Now that they are all in the correct units you solve gay-lusac's law to solve for V2. P1V1/T1 = P2V2/T2, cross multiply and you get P1V1T2 = P2V2T1.  Isolate V2 and you get V2 = P1V1T2/P2T1.  Put in your variables and you get (1.2atm)(75L)(323K) / (0.921atm)(278K) =  113.534 L