Topics you need to know for this question: Kinematic equations Rotational motion equation Projectile motion

1. A Baseball is thrown up into the air at an angle of 30 from a height of .5 m with an initial velocity of 48m/s. There is a bullseye 45m away. What is the Vxi? Vyi? Vxi=41.57m/s Vyi=24m/s Vxf @ bullseye? Vyf @ bullseye? (t=1.08s) Vxf=41.57m/s Vyf=13.2m/s Resultant Vf? 43.62m/s Resultant angle? 17.62 degrees 2. If the baseball hits the bullseye in the center and if the radius of the bullseye is .25m how high is the top of the bullseye? Don’t worry about this one. 3. In the center of the bullseye there is a bucket attached to a string, allowing the baseball to continue in a circular path of radius .5m. When the .35kg baseball hits the bullseye/bucket it begins traveling in the .5m radius circular path at the same final velocity it had when it hit. What is the Fcent on the baseball? =mv^2/r -> .35(43.62)^2/.5 = 1331.89N Assuming the baseball is swinging vertically, what is the tension in the string at the bottom of the loop? T-W=Fcent 1331.89 = T-3.5 T=1335.39N What is the tension in the string at an angle of 20 degrees up from the bottom of its path? T-W(x)=Fcent 1331.89=T-3.5sin(20) T=1333.09 120 degrees from the bottom? Don‘t worry about this one