University Physics: Mechanics

Slides:



Advertisements
Similar presentations
Chapter 4 The Laws of Motion Force Newton’s Laws Applications Friction.
Advertisements

Chapter 5 – Force and Motion I
1 Chapter Four Newton's Laws. 2  In this chapter we will consider Newton's three laws of motion.  There is one consistent word in these three laws and.
Newton’s Second Law The net force on a body is equal to the product of the body’s mass and its acceleration.
Ropes and Pulleys.
When a car accelerates forward on a level roadway, which force is responsible for this acceleration? State clearly which.
University Physics: Mechanics
Newton’s Laws of Motion (Applications)
Applying Newton’s Laws. A systematic approach for 1 st or 2 nd Law Problems 1.Identify the system to be analyzed. This may be only a part of a more complicated.
Chapter 5 Force and Motion (I) Kinematics vs Dynamics.
Newton’s 3rd Law of Motion By: Heather Britton. Newton’s 3rd Law of Motion Newton’s 3rd Law of Motion states Whenever one object exerts a force on a second.
General Physics 1, Additional questions By/ T.A. Eleyan
Newton’s Laws of Motion Problems MC Questions
Newton’s Laws Problems
A 6. 0-kg object undergoes an acceleration of 2. 0 m/s2
AP Physics B Summer Course 年AP物理B暑假班
Problems Chapter 4,5.
Newton’s Laws of Motion
I.Newton’s first law. II.Newton’s second law. III.Particular forces: - Gravitational - Gravitational - Weight - Weight - Normal - Normal - Tension - Tension.
Applications of Newton’s Laws of Motion
University Physics: Mechanics
PHYS16 – Lecture 10 & 11 Force and Newton’s Laws September 29 and October 1, 2010
1 Some application & Forces of Friction. 2 Example: When two objects of unequal mass are hung vertically over a frictionless pulley of negligible mass,
Physics 111: Mechanics Lecture 4
Applications & Examples of Newton’s Laws. Forces are VECTORS!! Newton’s 2 nd Law: ∑F = ma ∑F = VECTOR SUM of all forces on mass m  Need VECTOR addition.
Chapter 5 THE LAWS OF MOTION. Force, net force : Force as that which causes an object to accelerate. The net force acting on an object is defined as.
Lecture 7 Newton’s Laws of Motion. Midterm Test #1 - Thursday!  21 multiple-choice problems - A calculator will be needed. - CHECK YOUR BATTERIES! -
Physics 111 Practice Problem Statements 04 Force and Motion I: The Laws of Motion SJ 8th Ed.: Ch. 5.1 – 5.7 Contents: 5-2E, 5-7P, 5-9E, 5-29P*, 5-31P*,
University Physics: Mechanics Ch5. Newton’s Law of Motion Lecture 7 Dr.-Ing. Erwin Sitompul
University Physics: Mechanics Ch5. Newton’s Law of Motion Lecture 7 Dr.-Ing. Erwin Sitompul
University Physics: Mechanics Ch5. Newton’s Laws of Motion Lecture 8 Dr.-Ing. Erwin Sitompul
University Physics: Mechanics
PHY 151: Lecture Forces of Friction 5.9 Newton’s Second Law.
Lecture 5Purdue University, Physics 2201 Lecture 05 Forces and Motion beyond 1 D Textbook Sections 3.7, 4.1 PHYSICS 220.
Solving problems when  F = ma
University Physics: Mechanics
University Physics: Mechanics
Physics 218 Lecture 6: Dynamics Alexei Safonov.
University Physics: Mechanics
University Physics: Mechanics
Inclined Plane Problems
University Physics: Mechanics
Chapter 5 Force and Motion Friday, May 25, 2018 Chap 5.
AP Physics Review Ch 4 – Forces and Newton’s Laws of Motion
University Physics: Mechanics
Aim: How can we apply Newton’s Second Law?
Refresher: *Acceleration is only caused by an unbalanced net force acting on an object. F = ma F = F1 + F2 + … *The weight of an object is referred to.
Phys 270 Newton’s Laws.
University Physics: Mechanics
from rest down a plane inclined at an angle q with the horizontal.
Ch-5 Term 091 Help-Session.
APC -Unit 2.
Chapter 5 Force and Motion.
Fig. Q5.17, p.139.
Simple applications Of 1st & 2nd Laws.
University Physics: Mechanics
SPH4U1 “Free Body Diagrams”
Newton’s Laws: Practice Problems
Last Time: Dynamics: Forces
Frictional Forces.
Chapter 4 Connected Objects.
Motion in 2D and Pulleys Constant acceleration in 2-D Free fall in 2-D
Newton’s Laws: Practice Problems
Force Problems.
Have you ever used Mathematica?
Three masses are connected by light strings as shown in the figure
Chapter 5 – Force and Motion I
ΣFy = FT - Fg = ma FT = ma + mg = m (a + g) = 5 ( ) FT
A block of mass m resting on a horizontal
Aim: How do we solve static equilibrium problems?
Presentation transcript:

University Physics: Mechanics Lecture 8 Ch5. Newton’s Laws of Motion University Physics: Mechanics Dr.-Ing. Erwin Sitompul http://zitompul.wordpress.com 2015

Homework 7: Two Boxes and A Pulley A block of mass m1 = 3.7 kg on a frictionless plane inclined at angle θ = 30° is connected by a cord over a massless, frictionless pulley to a second block of mass m2 = 2.3 kg. What are: (a) the magnitude of the acceleration of each block, (b) the direction of the acceleration of the hanging block, and (c) the tension in the cord?

Solution of Homework 7 FN T T a a m1gsinθ m1gcosθ m2g m1g Forces on m1 along the x axis: Forces on m2 along the y axis: What is the meaning of negative sign?

Solution of Homework 7 (a) The magnitude of the acceleration of each block (b) The direction of the acceleration of the hanging block Assumption : The acceleration points upward Result : Negative value Conclusion : The true acceleration points downward Down (c) The tension in the cord

Applying Newton’s Law: Problem 3 A passenger of mass 71.43 kg stands on a platform scale in an elevator cab. We are concerned with the scale reading when the cab is stationary and when it is moving up or down. (a) Find a general solution for the scale reading, whatever the vertical motion of the cab. (b) What does the scale read if the cab is stationary or moving upward at a constant 0.5 m/s? (c) What does the scale read if the cab acceleration upward 3.2 m/s2 and downward at 3.2 m/s2?

Applying Newton’s Law: Problem 3 (a) Find a general solution for the scale reading, whatever the vertical motion of the cab. → The scale reading is equal to FN, which is the force exerted by the surface of the scale towards the passenger (b) What does the scale read if the cab is stationary or moving upward at a constant 0.5 m/s? In stationary condition or when moving upward with a constant velocity, the acceleration of passenger is zero

Applying Newton’s Law: Problem 3 (c) What does the scale read if the cab acceleration upward 3.2 m/s2 and downward at 3.2 m/s2? If the cab accelerates upward, the magnitude of acceleration is positive It the cab accelerates downward, the magnitude of acceleration is negative

Applying Newton’s Law: Problem 3 What does the scale read if, in case accident happens, the cab falls vertically downward? a = –g

Applying Newton’s Law: Problem 4 The figure below shows two blocks connected by a cord (of negligible mass) that passes over a frictionless pulley (also of negligible mass). One block has mass m1 = 2.8 kg; the other has mass m2 = 1.3 kg. Determine: (a) the magnitude of the blocks’ acceleration. (b) the tension in the cord. Atwood Machine

Applying Newton’s Law: Problem 4 Mass m1 Mass m2 The acceleration of m1 and m2 have the same magnitude a, oppose in direction. T a T a m1g m2g

Applying Newton’s Law: Problem 4 (a) The magnitude of the blocks’ acceleration What happen if m2 > m1? (b) The tension in the cord

Virtual Experiment: Atwood Machine Two masses of 550 g and 560 g are connected through a pulley to construct an Atwood machine. If the masses are released from rest, how much time is required for the masses to move a distance of 1 m?

Example: Particle Movement A 2 kg particle moves along an x axis, being propelled by a variable force directed along that axis. Its position is given by x = 3 m + (4 m/s)t + ct2 – (2 m/s3)t3, with x in meters and t in seconds. The factor c is a constant. At t = 3 s, the force on the particle has a magnitude of 36 N and is in the negative direction of the axis. What is c?

Hanging Chair A man sits in a chair that dangles from a massless rope, which runs over a massless, frictionless pulley and back down to the man’s hand. The combined mass of man and chair is 95 kg. With what force magnitude must the man pull on the rope if he is to rise (a) with a constant velocity and (b) with an upward acceleration of 1.3 m/s2? TA TA (a) TB TB Fg = mg (b) a Fg = mg

Hanging Chair Continuing the same problem, if the rope on the right extends to the ground and is pulled by a co-worker, with what force magnitude must the co-worker pull for the main to rise (c) with a constant velocity and (d) with an upward acceleration of 1.3 m/s2? TC (c) TB Fg = mg (d) a Fg = mg What is the magnitude of the force on the ceiling from the pulley system in each of 4 cases?

Homework 8: The Traffic Light A traffic light weighing 122 N hangs from a cable tied to two other cables fastened to a support, as in the figure below. The upper cables make angles of 37° and 53° with the horizontal. These upper cables are not as strong as the vertical cable and will break if the tension in them exceeds 100N. Will the traffic light remain hanging in this situation, or will one of the cables break?

Homework 8A Two forces are applied to a ring that is lying on a frictionless surface. It is shown on the figure from the bird’s-eye-view. If the mass of the ring is 6 kg, determine the position of the ring 2 seconds after the two forces are applied. 2. Joe’s Advertising wishes to hang a sign weighing 750.0 N so that cable A, attached to the store makes a 30.0° angle, as shown in the figure. Cable B is horizontal and attached to and adjoining building. What is the tension in cable B?

Homework 8B θ As your jet plane speeds down the runway on takeoff, you decide to determine its acceleration, so you take out your yo-yo and note that when you suspend it, the string makes an angle of 22° with the vertical (see figure). (a) What is the acceleration of the plane? (b) If the mass of the yo-yo is 40 g, what is the tension in the string? Hint: Decompose the tension T. a 2. In the next figure, let the mass of the block be 8.5 kg and the angle θ be 30°. Find (a) the tension in the cord and (b) the normal force acting on the block. (c) If the cord is cut, find the elevation decrease of the mass after moving for 0.8 s (assuming it does not reach the floor).