Building Java Programs

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Presentation transcript:

Building Java Programs Chapter 12 introduction to recursion reading: 12.1

Recursion recursion: The definition of an operation in terms of itself. Solving a problem using recursion depends on solving smaller occurrences of the same problem. recursive programming: Writing methods that call themselves to solve problems recursively. An equally powerful substitute for iteration (loops) Particularly well-suited to solving certain types of problems

Getting down stairs Need to know two things: Most code will look like: Getting down one stair Recognizing the bottom Most code will look like: if (simplest case) { compute and return solution } else { divide into similar subproblem(s) solve each subproblem recursively assemble the overall solution }

Recursion and cases Every recursive algorithm involves at least 2 cases: base case: A simple occurrence that can be answered directly. recursive case: A more complex occurrence of the problem that cannot be directly answered, but can instead be described in terms of smaller occurrences of the same problem. Some recursive algorithms have more than one base or recursive case, but all have at least one of each. A crucial part of recursive programming is identifying these cases.

Recursion vs Iteration public static void writeStars(int n) { while (n > 0) { System.out.print("*"); n--; } System.out.println(); if (n == 0) { } else { writeStars(n – 1);

Recursion vs Iteration public static void writeStars(int n) { while (n > 0) { System.out.print("*"); n--; } System.out.println(); // base case. assert: n == 0 if (n == 0) { System.out.println(); // base case } else { writeStars(n – 1);

Recursion vs Iteration public static void writeStars(int n) { while (n > 0) { // "recursive" case System.out.print("*"); // small piece of problem n--; } System.out.println(); if (n == 0) { } else { // "recursive" case. assert: n > 0 writeStars(n – 1);

Recursion vs Iteration public static void writeStars(int n) { while (n > 0) { // "recursive" case System.out.print("*"); n--; // make the problem smaller } System.out.println(); if (n == 0) { } else { // "recursive" case. assert: n > 0 writeStars(n – 1); // make the problem smaller

Exercise Write a recursive method reverseLines that accepts a file Scanner and prints the lines of the file in reverse order. Example input file: Expected console output: I have eaten the icebox the plums that were in that were in the plums the icebox I have eaten What are the cases to consider? How can we solve a small part of the problem at a time? What is a file that is very easy to reverse?

Tracing our algorithm call stack: The method invocations currently running reverseLines(new Scanner("poem.txt")); public static void reverseLines(Scanner input) { if (input.hasNextLine()) { String line = input.nextLine(); // "I have eaten" reverseLines(input); System.out.println(line); } public static void reverseLines(Scanner input) { if (input.hasNextLine()) { String line = input.nextLine(); // "the plums" reverseLines(input); System.out.println(line); } public static void reverseLines(Scanner input) { if (input.hasNextLine()) { String line = input.nextLine(); // "that were in" reverseLines(input); System.out.println(line); } public static void reverseLines(Scanner input) { if (input.hasNextLine()) { String line = input.nextLine(); // "the icebox" reverseLines(input); System.out.println(line); } public static void reverseLines(Scanner input) { if (input.hasNextLine()) { // false ... } input file: output: I have eaten the plums that were in the icebox the icebox that were in the plums I have eaten