Homework: pg. 446 74.) P(A and B)=0.46*0.32=0.1472 78.) A. 0.25 B.) 0.3333 79.) .3142; If A and B were independent, then the conditional probability of.

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Homework: pg. 446 74.) P(A and B)=0.46*0.32=0.1472 78.) A. 0.25 B.) 0.3333 79.) .3142; If A and B were independent, then the conditional probability of A given B would equal the probability of A.

6.3 Tree Diagrams

Example 1: Probability of having a certain disease=.05 If you have the disease, probability of testing positive is .98 Probability of false positive is .10 What is the probability that you have the disease if you test positive?

Make a Tree Diagram!!! Tested Positive Yes, you have the disease Tested Negative Tested Positive No, you don’t have the disease Tested Negative

Example 2: pg. 446 #72, 73 At a self service gas station, 40% of the customers pump regular gas, 35% pump midgrade, and 25% pump premium gas. Of those who pump regular, 30% pay at least $20. Of those who pump midgrade, 50% pay at least $20. And of those who pump premium, 60% pay at least $20. What is the probability that the next customer pays at least $20? What percent of the customers who pay at least $20 pump premium?

Homework Pg. 451 #82-84