Heating curves and DH temperature added energy

Heating curves and DH gas liquid temperature solid added energy

Heating curves and DH gas temperature liquid melting/ freezing pt solid added energy

Heating curves and DH boiling/ cond. pt gas temperature liquid melting/ freezing pt temperature solid added energy

Heating curves and DH boiling/ cond. pt gas temperature liquid boiling/condensing occurring here melting/freezing occurring here boiling/ cond. pt gas liquid melting/ freezing pt temperature solid added energy

How is the total enthalpy change (DH) calculated for a substance whose temperature change includes a change in state?

temperature Dt of solid absorbing energy added energy

temperature DH = m x Csolid x Dt added energy

as a solid melts becomes potential energy, so no Dt the energy absorbed as a solid melts becomes potential energy, so no Dt temperature DH = m x Csolid x Dt added energy

DH = DHfus x # mols temperature DH = m x Csolid x Dt added energy

Dt of liquid absorbing energy temperature DH = DHfus x # mols DH = m x Csolid x Dt added energy

DH = m x Cliquid x Dt temperature DH = DHfus x # mols DH = m x Csolid x Dt added energy

as a liquid boils becomes potential energy, so no Dt the energy absorbed as a liquid boils becomes potential energy, so no Dt DH = DHfus x # mols DH = m x Cliquid x Dt temperature DH = m x Csolid x Dt added energy

DH = DHvap x # mols temperature DH = DHfus x # mols DH = m x Cliquid x Dt temperature DH = m x Csolid x Dt added energy

Dt of gas absorbing energy DH = DHvap x # mols temperature DH = DHfus x # mols DH = m x Cliquid x Dt temperature DH = m x Csolid x Dt added energy

DH = m x Cgas x Dt DH = DHvap x # mols temperature DH = DHfus x # mols DH = m x Cliquid x Dt temperature DH = m x Csolid x Dt added energy

DH = m x Cgas x Dt DH = DHvap x # mols DH = DHfus x # mols DH = m x Cliquid x Dt temperature DH = m x Csolid x Dt added energy

being heated will be the sum of the DH of any Dt occurring plus The DH of any substance being heated will be the sum of the DH of any Dt occurring plus DH of any phase change occurring DH = m x Cgas x Dt DH = DHvap x # mols DH = DHfus x # mols DH = m x Cliquid x Dt temperature DH = m x Csolid x Dt added energy

DH = m x Cgas x Dt DH = DHvap x # mols DH = DHfus x # mols The DH of any substance being heated will be the sum of the DH of any Dt occurring plus DH of any phase change occurring DH = m x Cgas x Dt DH = DHvap x # mols DH = DHfus x # mols DH = m x Cliquid x Dt temperature DH = m x Csolid x Dt added energy

DH = m x Cgas x Dt DH = DHvap x # mols temperature DH = DHfus x # mols EXAMPLE: What is DH for 10 g water with a total Dt from -20 oC to +50 oC? DH = m x Cgas x Dt DH = DHvap x # mols DH = DHfus x # mols DH = m x Cliquid x Dt temperature DH = m x Csolid x Dt added energy

50 oC temperature 0 oC -20 oC added energy EXAMPLE: What is DH for 10 g water with a total Dt from -20 oC to +50 oC? 50 oC temperature 0 oC -20 oC added energy

use the following values: EXAMPLE: What is DH for 10 g water with a total Dt from -20 oC to +50 oC? use the following values: Cice = 2.1 J/goc, DHfus H2O = 6.01 kJ/mol, CH2O liq = 4.186 J/goC 50 oC temperature 0 oC -20 oC added energy

use the following values: EXAMPLE: What is DH for 10 g water with a total Dt from -20 oC to +50 oC? use the following values: Cice = 2.1 J/goc, DHfus H2O = 6.01 kJ/mol, CH2O liq = 4.186 J/goC 50 oC DH3 = m x Cliquid x Dt DH2 = DHfus x # mols temperature 0 oC DH1 = m x Csolid x Dt -20 oC added energy

DH1 = 10g x 2.1 J/goC x 20oC use the following values: EXAMPLE: What is DH for 10 g water with a total Dt from -20 oC to +50 oC? use the following values: Cice = 2.1 J/goc, DHfus H2O = 6.01 kJ/mol, CH2O liq = 4.186 J/goC 50 oC DH3 = m x Cliquid x Dt DH2 = DHfus x # mols temperature 0 oC DH1 = 10g x 2.1 J/goC x 20oC -20 oC added energy

use the following values: DH2=10 g x 1mol/18g x 6.01kJ/mol EXAMPLE: What is DH for 10 g water with a total Dt from -20 oC to +50 oC? use the following values: Cice = 2.1 J/goc, DHfus H2O = 6.01 kJ/mol, CH2O liq = 4.186 J/goC 50 oC DH2=10 g x 1mol/18g x 6.01 kJ/mol DH3 = m x Cliquid x Dt temperature 0 oC DH1 = 10g x 2.1 J/goC x 20oC -20 oC added energy

DH3 = 10g x 4.186 J/goC x 50 oC use the following values: EXAMPLE: What is DH for 10 g water with a total Dt from -20 oC to +50 oC? use the following values: Cice = 2.1 J/goc, DHfus H2O = 6.01 kJ/mol, CH2O liq = 4.186 J/goC DH3 = 10g x 4.186 J/goC x 50 oC 50 oC DH2=10 g x 1mol/18g x 6.01 kJ/mol temperature 0 oC DH1 = 10g x 2.1 J/goC x 20oC -20 oC added energy

total DH = DH1 + DH2 + DH3 use the following values: EXAMPLE: What is DH for 10 g water with a total Dt from -20 oC to +50 oC? use the following values: Cice = 2.1 J/goc, DHfus H2O = 6.01 kJ/mol, CH2O liq = 4.186 J/goC total DH = DH1 + DH2 + DH3 DH3 = 10g x 4.186 J/goC x 50 oC 50 oC DH2=10 g x 1mol/18g x 6.01 kJ/mol temperature 0 oC DH1 = 10g x 2.1 J/goC x 20oC -20 oC added energy

total DH = DH1 + DH2 + DH3 = 420 J + 3340 J + 2093 J EXAMPLE: What is DH for 10 g water with a total Dt from -20 oC to +50 oC? use the following values: Cice = 2.1 J/goc, DHfus H2O = 6.01 kJ/mol, CH2O liq = 4.186 J/goC total DH = DH1 + DH2 + DH3 = 420 J + 3340 J + 2093 J DH3 = 10g x 4.186 J/goC x 50 oC 50 oC DH2=10 g x 1mol/18g x 6.01 kJ/mol temperature 0 oC DH1 = 10g x 2.1 J/goC x 20oC -20 oC added energy

total DH = DH1 + DH2 + DH3 5853 J = 420 J + 3340 J + 2093 J EXAMPLE: What is DH for 10 g water with a total Dt from -20 oC to +50 oC? use the following values: Cice = 2.1 J/goc, DHfus H2O = 6.01 kJ/mol, CH2O liq = 4.186 J/goC total DH = DH1 + DH2 + DH3 5853 J = 420 J + 3340 J + 2093 J DH3 = 10g x 4.186 J/goC x 50 oC 50 oC DH2=10 g x 1mol/18g x 6.01 kJ/mol temperature 0 oC DH1 = 10g x 2.1 J/goC x 20oC -20 oC added energy

It takes 5853 joules to heat up 10 grams EXAMPLE: What is DH for 10 g water with a total Dt from -20 oC to +50 oC? It takes 5853 joules to heat up 10 grams of water from -20 oC to +50 oC. DH3 = 10g x 4.186 J/goC x 50 oC 50 oC DH2=10 g x 1mol/18g x 6.01 kJ/mol temperature 0 oC DH1 = 10g x 2.1 J/goC x 20 oC -20 oC added energy

It takes 5853 joules to heat up 10 grams EXAMPLE: What is DH for 10 g water with a total Dt from -20 oC to +50 oC? It takes 5853 joules to heat up 10 grams of water from -20 oC to +50 oC. DH3 = 10g x 4.186 J/goC x 50 oC 50 oC DH2=10 g x 1mol/18g x 6.01 kJ/mol temperature 0 oC DH1 = 10g x 2.1 J/goC x 20 oC -20 oC added energy

5853 J It takes 5853 joules to heat up 10 grams EXAMPLE: What is DH for 10 g water with a total Dt from -20 oC to +50 oC? It takes 5853 joules to heat up 10 grams of water from -20 oC to +50 oC. 50 oC temperature 0 oC -20 oC 5853 J added energy