Final Review Jeopardy Chapter Chapter Chapter 3 100

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Presentation transcript:

Final Review Jeopardy Chapter 1 100 Chapter 2 100 Chapter 3 100 200 Chapter 1 200 Chapter 2 200 Chapter 4 200 Chapter 5 200 Chapter 1 300 Chapter 4 300 Chapter 5 300 Chapter 2 300 Chapter 3 300 Chapter 1 400 Chapter 2 400 Chapter 3 400 Chapter 4 400 Chapter 5 400 Chapter 1 500 Chapter 2 500 Chapter 3 500 Chapter 4 500 Chapter 5 500

Chapter 1 100 Simplify [7 • (4 + 5)] + 2 65

Chapter 1 200 Evaluate 5p - 2q when p = -2 and q = 3 -16

Chapter 1 300 A basketball court is 35 yards long and 25 yards wide. How many square yards? 875

Chapter 1 400 Evaluate the Expression (x + y)2 for x = 3 & y = 7 100

Chapter 1 500 Evaluate the Expression 12 + (5 • 3)2 - 6. 231

Chapter 2 100 Express the phrase“The Product of a number and 7 is 42” as an equation. 7x = 42

Chapter 2 200 Evaluate |y| + |x| when y = -7 and x = -3 10

Chapter 2 300 Evaluate -16 - 4 + (-12) -32

Chapter 2 400 Simplify: -(-5) - (-4) + 9 18

Chapter 2 500 -3 -6 -4 -7 7 -4 -3 3 - 1 1 10 -7

Chapter 3 100 Simplify: 3(-2 - x) -5(3 - x) 2x - 21

Chapter 3 200 Evaluate 3ab when a=5 & b=7 4a - 3 105 17

Chapter 3 300 Add 7 to both sides State the 1st step for solving the equation: x - 7 = 28 Add 7 to both sides

Chapter 3 400 Solve ½x = 16 X = 32

Chapter 3 500 Solve 7x - 3 = 60 X = 9

Chapter 4 100 Graph y = 2/3x + 3

Chapter 4 200 Graph 3x + 2y = 6 using the x and y intercepts.

Click here for the Daily Double Chapter 4 300 Click here for the Daily Double

Chapter 4 ??? Graph y = -3

Chapter 4 400 Graph 2x - 4 = y

Chapter 4 500 Graph 3x + 2y = 6

Solve the absolute value equation |x + 4| = 7 Chapter 5 100 Solve the absolute value equation |x + 4| = 7 X = 3 & x = -11

Chapter 5 200 The points (1,6) & (3,-4) Find the Slope m = -10/2 = -5

Chapter 5 300 y = -4/3x + 2 (x1,y1) = (0,2) & (x2,y2) = (3,-2) What is the slope-intercept form of the equation if (x1,y1) = (0,2) & (x2,y2) = (3,-2) y = -4/3x + 2

Chapter 5 400 What is the slope-intercept form of the equation if (x1,y1) = (5,0) & (x2,y2) = (0,-3) y = 3/5x - 3

Chapter 5 500 Graph the absolute value equation y = 3|x + 2| - 3

Chapter 4 400 Y X