Review Reaction mechanism Br2(l) + C5H12(l)  C5H11Br(l) + HBr(l)

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Presentation transcript:

Review Reaction mechanism Br2(l) + C5H12(l)  C5H11Br(l) + HBr(l) step 1 Br2  step 2 Br. + C5H12  HBr + C5H11. C5H11. + Br.  C5H11Br step 3 overall Br2 + C5H12  C5H11Br + HBr

Br2(l) + C5H12(l)  C5H11Br(l) + HBr(l) 2 Br.  step 1 Br2 HBr + C5H11.  step 3 C5H11. + Br. C5H11Br assume step 2 is rate determining (slow) rate = k2 [Br.] [C5H12] Br.= intermediate Keq = [Br.]2 [Br2] rate = k2 k’[Br2]1/2 [C5H12] rate = k’[Br2]1/2 [C5H12] [Br.] = Keq1/2 [Br2]1/2 11/2 order reaction

bimolecular elementary steps increase [react]  increase rate of reaction increase T  increase rate of reaction increase number of collisions increase force of collisions

minimum energy required for reaction: T2 > T1 # molecules Kinetic Energy minimum energy required for reaction: activation energy = Ea

Arrhenius Equation k = z p e-Ea/RT T dependence of a rate constant, k a) increases b) decreases with T k a) decreases b) increases with Ea Ea = activation energy (kJ/mol) R = gas constant (8.314 x 10-3kJ/K mol) T = temperature (K) z = collision frequency p = steric factor (<1)

k = A e-Ea/RT p = steric factor z = collision frequency combine to give A k = A e-Ea/RT

Arrhenius Equation k = A e-Ea/RT ln k = - (Ea/R) (1/T) + ln A ln A y = m x + b plot ln k v.s. 1/T slope = -Ea/R intercept = ln A ln (k2/ k1) = (Ea /R) (1/T1 - 1/T2)

A-B + C A...B...C A + B-C activated complex P.E. is at a maximum transition state A + B-C

Hrxn A-B + C A...B...C A + B-C Eaf Eab activated complex reactants P.E. Hrxn products Reaction coordinate A-B + C A...B...C A + B-C

Hrxn exothermic Eab Eaf > endothermic Eaf Eab activated complex reactants P.E. Hrxn products Reaction coordinate exothermic Eab Eaf > endothermic

exothermic Eab Eaf > large Ea = slow rate endothermic Eab Eaf < activated complex products reactants Eaf Eab P.E. Reaction coordinate exothermic Eab Eaf > large Ea = slow rate endothermic Eab Eaf <

faster forward reaction ( kf ) lowers Ear  - catalyst + catalyst lowers Eaf  faster forward reaction ( kf ) lowers Ear  faster reverse reaction ( kr ) Keq unchanged and H kf = Keq kr

Br2(l) + C5H12(l)  C5H11Br(l) + HBr(l) Hrxn < 0 Ea Reaction coordinate P.E. Br2 + C5H12 Hrxn C5H11Br + HBr

Br2(l) + C5H12(l)  C5H11Br(l) + HBr(l) step 1 Br2 2 Br. hn Br2(l) + C5H12(l)  C5H11Br(l) + HBr(l) step 1 Br2 2 Br. h step 2 Br. + C5H12  HBr + C5H11. step 3 C5H11. + Br.  C5H11Br Ea Ea Ea HBr + C5H11. + Br. 2Br. + C5H12 C5H12 + Br2 P.E. C5H11Br + HBr