Projectiles Launched at an Angle

Projectiles Launched at an Angle (in general) X Y d= vi= vcosθ vi= vsinθ vf= a= 0 a=-9.8m/s2 t=

Maximum Height X Y d= vi= vcosθ vi= vsinθ vf= vcosθ vf= 0 a= 0 a=-9.8m/s2 t= vertical speed = 0 θ

Problem #1 X Y d= vi= 30cos35 vi= 30sin35 vf= 30cos35 vf= 0 a= 0 What is the maximum height above the ground reached by a cannonball shot at 30 m/s in a direction 35 degrees above the ground? X Y d= vi= 30cos35 vi= 30sin35 vf= 30cos35 vf= 0 a= 0 a=-9.8m/s2 t= 30 m/s 35º

Displacement in the y direction is zero Horizontal Range X Y d= d= 0 vi= vcosθ vi= vsinθ vf= vcosθ vf= -vsinθ a= 0 a=-9.8m/s2 t= Displacement in the y direction is zero θ vertical speed = negative of original

Problem #2 X Y d= d= 0 vi= 30cos35 vi= 30sin35 vf= 30cos35 What is the maximum horizontal range reached by a cannonball shot at 30 m/s in a direction 35 degrees above the ground? X Y d= d= 0 vi= 30cos35 vi= 30sin35 vf= 30cos35 vf= -30sin35 a= 0 a=-9.8m/s2 t= 30 m/s 35º