Warmup: Decompose the following functions

Slides:



Advertisements
Similar presentations
2.4 The Chain Rule If f and g are both differentiable and F is the composite function defined by F(x)=f(g(x)), then F is differentiable and F′ is given.
Advertisements

The Chain Rule Section 3.6c.
3 DERIVATIVES.
Clicker Question 1 What is the instantaneous rate of change of f (x ) = sin(x) / x when x =  /2 ? A. 2/  B. 0 C. (x cos(x) – sin(x)) / x 2 D. – 4 / 
Copyright © Cengage Learning. All rights reserved. 2 Functions and Their Graphs.
The Chain Rule Section 2.4.
Section 2.4 – The Chain Rule. Example 1 If and, find. COMPOSITION OF FUNCTIONS.
Section 2.4 – The Chain Rule
Warm Up: h(x) is a composite function of f(x) and g(x). Find f(x) and g(x)
Lesson 3-R Review of Differentiation Rules. Objectives Know Differentiation Rules.
In this section, we will learn about: Differentiating composite functions using the Chain Rule. DIFFERENTIATION RULES 3.4 The Chain Rule.
3 DERIVATIVES. In this section, we will learn about: Differentiating composite functions using the Chain Rule. DERIVATIVES 3.5 The Chain Rule.
Copyright © Cengage Learning. All rights reserved. 2 Derivatives.
Math 1304 Calculus I 3.4 – The Chain Rule. Ways of Stating The Chain Rule Statements of chain rule: If F = fog is a composite, defined by F(x) = f(g(x))
MAT 213 Brief Calculus Section 3.4 The Chain Rule.
Mrs. Volynskaya Combinations of Functions
Integration by Substitution Antidifferentiation of a Composite Function.
2.4 The Chain Rule Greg Kelly, Hanford High School, Richland, WashingtonPhoto by Vickie Kelly, 2002.
3.4 - The Chain Rule. The Chain Rule: Defined If f and g are both differentiable and F = f ◦ g is the composite function defined by F(x) = f(g(x)), then.
Calculus Section 2.4 The Chain Rule. Used for finding the derivative of composite functions Think dimensional analysis Ex. Change 17hours to seconds.
The Chain Rule is used for a composition of two functions (in other words, a function within a function) Example: Arnold the paper boy gets paid $25 dollars.
Thevisualclassroom.com 6.2 Rates of Change for Composite Functions - The Chain Rule Therefore if h(x) = (f o g)(x), then h ´ (x) = f ´ (g(x)) · g ´ (x)
Math on the Mind. Composition of Functions Unit 3 Lesson 7.
Section 3.4 The Chain Rule. Consider the function –We can “decompose” this function into two functions we know how to take the derivative of –For example.
In this section, we will investigate how to take the derivative of a function that is the composition of multiple functions.
Objectives: 1. Be able to find the derivative of function by applying the Chain Rule Critical Vocabulary: Chain Rule Warm Ups: 1.Find the derivative of.
Lesson 3-5 Chain Rule or U-Substitutions. Objectives Use the chain rule to find derivatives of complex functions.
1 The Chain Rule Section After this lesson, you should be able to: Find the derivative of a composite function using the Chain Rule. Find the derivative.
Chain Rule 3.5. Consider: These can all be thought of as composite functions F(g(x)) Derivatives of Composite functions are found using the chain rule.
Chain Rule – Differentiating Composite Functions.
In this section, we will learn about: Differentiating composite functions using the Chain Rule. DERIVATIVES 3.5 The Chain Rule.
The Chain Rule Composite Functions When a function is composed of an inner function and an outer function, it is called a “composite function” When a.
2.4: THE CHAIN RULE. Review: Think About it!!  What is a derivative???
B2.4 - Rules of Differentiation - Chain Rule MCB4U & IB HL/SL - Santowski.
The CHAIN Rule The first of the really cool things that we learn in Calculus.
1.7 Copyright © 2014 Pearson Education, Inc. The Chain Rule OBJECTIVE Find the composition of two functions. Differentiate using the Extended Power Rule.
3.1 The Product and Quotient Rules & 3.2 The Chain Rule and the General Power Rule.
Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley The Chain Rule OBJECTIVES  Find the composition of two functions.  Differentiate.
2-1 The Derivative and the Tangent Line Problem 2-2 Basic Differentiation Rules and Rates of Change 2-3 Product/Quotient Rule and Higher-Order Derivatives.
3.6 The Chain Rule Y= f(g(x)) Y’=f’(g(x)) g’(x). Chain rule Unlocks many derivatives.
Chapter 3 Techniques of Differentiation
Composition of functions
11.4 The Chain Rule.
Ch. 1 – Functions and Their Graphs
Copyright © Cengage Learning. All rights reserved.
Combinations of Functions: Composite Functions 1.8
DIFFERENTIATION RULES
Combinations of Functions: Composite Functions 1.8
Lesson 4.5 Integration by Substitution
Calculus Section 3.6 Use the Chain Rule to differentiate functions
Copyright © Cengage Learning. All rights reserved.
Product and Quotient Rules
4-2 Operations on Functions
2.4 The Chain Rule Use the Chain Rule to find derivative of a composite function. Use the General Power Rule to find derivative of a function. Simplify.
4-2 Operations on Functions
The Chain Rule Theorem Chain Rule
Combinations of Functions:
Math 180 Packet #6 The Chain Rule. Math 180 Packet #6 The Chain Rule.
The Chain Rule Find the composition of two functions.
Copyright © Cengage Learning. All rights reserved.
1.8 Notes: Composite Functions
Copyright © Cengage Learning. All rights reserved.
COMPOSITION OF FUNCTIONS
4.5 Integration by substitution
Substitution Lesson 7.2.
Integration by Substitution
3.6 – The Chain Rule.
Objective: To integrate functions using a u-substitution
Chain Rule Chain Rule.
Lesson 59 – Derivatives of Composed Functions – The Chain Rule
Presentation transcript:

Warmup: Decompose the following functions Lesson: ____ Section: 3.4 The Chain Rule Warmup: Decompose the following functions h(x) = f(g(x)) Outer Function Inner Function Ex. ℎ 𝑥 = 2𝑥+1 Ex. ℎ 𝑥 = 𝑒 𝑥 Ex. ℎ 𝑥 = 1 (𝑥 3 +2𝑥) 2 u = g(x) = 2x + 1 𝒇 𝒖 = 𝒖 u = g(x) = 𝒇 𝒖 = u = g(x) = 𝒇 𝒖 =

If f and g are differentiable functions, then 𝐼𝑓 𝑢=𝑔 𝑥 , 𝑦=𝑓 𝑢 , 𝑡ℎ𝑒𝑛 𝑦=𝑓(𝑔 𝑥 ) A small change in x will generate a small change in u which, in turn, generates a small change in y x u y g(x) f(u) f(g(x)) 𝑑𝑦 𝑑𝑥 = 𝑑𝑦 𝑑𝑢 ∙ 𝑑𝑢 𝑑𝑥 𝑑 𝑑𝑥 𝑓(𝑔 𝑥 ) 𝑓′ 𝑢 g′ 𝑥 The Chain Rule If f and g are differentiable functions, then 𝑑 𝑑𝑥 𝑓(𝑔 𝑥 )= 𝑓 ′ (𝑔 𝑥 )∙𝑔′(𝑥) “The derivative of a composite function is… The derivative of the outer function(evaluated at the inner) multiplied by the derivative of the inner.”

= 𝑑𝐿 𝑑𝑇 = 𝑑𝑇 𝑑𝑡 = 𝑑𝐿 𝑑𝑡 = 𝑑𝐿 𝑑𝑇 ∙ 𝑑𝑇 𝑑𝑡 = 2 𝑐𝑚 ℃ 3 ℃ ℎ𝑟 = 6 𝑐𝑚 ℎ𝑟 Suppose the length L, in cm of a steel bar depends on the air temperature, T in C and Temperature depends on time, t, measured in hours. If the length of the bar increases by 2 cm for every degree increase in temperature, and the temperature increases by 3 C per hour, how fast is the length of the bar increasing? What are the units? t T L L depends on T and T depends on t Rate L is increasing with respect to T = 𝑑𝐿 𝑑𝑇 =2 𝑐𝑚 ℃ Rate T is increasing with respect to t = 𝑑𝑇 𝑑𝑡 =3 °𝐶 ℎ𝑟 Rate L is increasing at with respect to t = 𝑑𝐿 𝑑𝑡 = 𝑑𝐿 𝑑𝑇 ∙ 𝑑𝑇 𝑑𝑡 = 2 𝑐𝑚 ℃ 3 ℃ ℎ𝑟 = 6 𝑐𝑚 ℎ𝑟

Practice these suckas! Ex. 𝑥 2 +1 100 Ex. 3 𝑥 2 +5𝑥−2 Ex. 3 𝑥 +2 3

Ex. 1 𝑥 2 + 𝑥 4 Ex. 𝑒 𝑥 2

Reviewing the concept… Ex. y is a function of 𝑥. 𝑦=𝑓 𝑥 𝑑 𝑑𝑥 𝑥= 𝑑 𝑑𝑥 𝑥 2 = 𝑑 𝑑𝑥 𝑦 2 = 1 Extending the idea a little further… If 𝑦=𝑓 𝑥 . 𝑑 𝑑𝑥 3𝑥𝑦 2 = 3∙ 𝑑 𝑑𝑥 𝑥 𝑦 2 2𝑥 3∙ 1 𝑦 2 + 𝑥 ( ) 2𝑦∙𝑦′ 2𝑦∙𝑦′ 3 𝑦 2 +6𝑥𝑦∙𝑦′ You fools want more practice? Try #4, 28, 36, 50, 54, 56 or even 46 Hint: Think of this as 𝒅 𝒅𝒙 𝒇 𝒙 𝟐

Ex. Try d dx x 2 +1 100 again without declaring new variables.

Try slaying a dragon! Apply the chain rule multiple times… Ex. d dx 𝑒 − 𝑥 7 +5