Percentage Composition Chapter 8 Percentage Composition.

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Presentation transcript:

Percentage Composition Chapter 8 Percentage Composition

Water is made of hydrogen and oxygen Water is made of hydrogen and oxygen. How many grams of each are in the sample of water below?

Percent Composition % = Percent composition is the percent by mass of an element within a compound. Divide the mass of each element by the formula mass of the compound Mass of element % = X 100 Formula Mass of compound

Percent Composition of H2O 2 X H = 2 X 1.0 g = 2.0 g 1 X O = 1 X 16.0 g = 16.0 g gram formula mass = 2.0 g + 16.0 g = 18.0 g % H = 2.0g X 100 = 11.2% 18.0g % O = 16.0g X 100 = 88.8%

Percent Composition of H2O 2 X H = 2 X 1.0 g = 2.0 g 1 X O = 1 X 16.0 g = 16.0 g gram formula mass = 2.0 g + 16.0 g = 18.0 g % H = 2.0g X 100 = 11.2% 18.0g % O = 16.0g X 100 = 88.8% What does this mean?

Pure water’s mass is 11.2% hydrogen and 88.8% oxygen. (0.112)(128.98g) = 14.45g H (.888)(128.98g) = 114.53g O or 128.98g – 14.45g = 114.53g O 11.2% H 88.8% O

Percentage Composition Remember that you have to calculate the formula mass! The problem doesn't say to do so...

Determine the Percent Composition of C6H12O6

Determine the Percent Composition of C6H12O6 6 X C = 6 X 12.0 g = 72.0g 12 X H = 12 X 1.0g = 12.0g 6 X O = 6 X 16.0g = 96.0g gfm = 180.0 grams/mole

Determine the Percent Composition of C6H12O6 6 X C = 6 X 12.0 g = 72.0g 12 X H = 12 X 1.0g = 12.0g 6 X O = 6 X 16.0g = 96.0g gfm = 180.0 grams/mole % C = % H = % O = (72.0g/180.0g) X 100 = 40.0% (12.0g/180.0g) X 100 = 6.67% (96.0g/180.0g) X 100 = 53.3%

How many grams of carbon are in 156g C6H12O6 6 (156g)(0.400) = 62.4g carbon 12 6 Molar % C = % H = % O = (72.0g/180.0g) X 100 = 40.0% (12.0g/180.0g) X 100 = 6.67% (96.0g/180.0g) X 100 = 53.3%

What is this? a

Iron Pyrite “Fool’s Gold” (FeS2) a

How many grams of sulfur are in this 28.8g sample of iron pyrite FeS2?

How many grams of sulfur are in this 28.8g sample of iron pyrite FeS2?

How many grams of sulfur are in this 28.8g sample of iron pyrite FeS2? 55.8 + 2( 32.1) = 120.0 g/mol %S = 64.2/120.0 x 100= 53.5%S 28.8g x 0.535 = 15.4g S a

Homework (Due in 2 days). Percentage Composition Worksheet