Estimating Crowds.

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Presentation transcript:

Estimating Crowds

WARM UP What is the largest gathering of people have you ever been involved in? How many people were involved? How do you think the event counted the people?

Estimating Crowds 5 Feet

Use the previous value to estimate the size of a crowd that is 10 feet deep on both sides of the street standing along a 1-mile section of a parade route. {10 Feet {10 Feet 1 Mile = 5,280 Feet

So our ratio is ________ Area = 5,280 x 10 = 52,800 ft2 Use the previous value to estimate the size of a crowd that is 10 feet deep on both sides of the street standing along a 1-mile section of a parade route. So our ratio is ________ Area = 5,280 x 10 = 52,800 ft2 Multiply the ratio by the area: ________ x 52,800 =____________ x 2 Final Answer: ____________

Our ratio is The area = 52,800 ft2 x 52,800 =21,120 x 2 One rule of thumb for estimating crowds is that each person occupies 2.5 ft2. Use this rule to estimate the size of the crowd. Our ratio is The area = 52,800 ft2 x 52,800 =21,120 x 2 Final Answer: 42,240

Our ratio is 6/9 Area = 3 yd. x 18 ft. = 9 ft. x 18 ft. = 162 ft. Six people fit comfortably in a 3 ft. by 3 ft. area. Use this value to estimate the size of a crowd that is 3 yards deep and 18 feet long. Our ratio is 6/9 Area = 3 yd. x 18 ft. = 9 ft. x 18 ft. (*Units are based on the ratio’s units) = 162 ft. 6/9 x 162 = 108 people

Our ratio is 9/16 ft. Area = 2 yd. x 1 mile. = 6 ft. x 5,280 ft. Nine people fit comfortably in a 4 ft. by 4 ft. area. Use this value to estimate the size of a crowd that is 2 yards deep and 1 mile long. Our ratio is 9/16 ft. Area = 2 yd. x 1 mile. = 6 ft. x 5,280 ft. (*Units are based on the ratio’s units) = 31,680 ft. 9/16 x 31,680 = 17,820 people

1 mile = 5,280 feet 12 inches = 1 foot 5,280 x 12 = 63,360 in. When the PS4 was released, the line was single file for 1 mile. If each person occupies 18 inches, how many were in the line? 1 mile = 5,280 feet 12 inches = 1 foot 5,280 x 12 = 63,360 in. 63,360 / 18 = 3,520 people

Practice Problem A basketball court is 94 feet by 50 feet. Eight fans can fit next to each other in a 3 ft. by 3 ft. area. How many kids would you estimate can fit side by side over the entire floor? 94 x 50 = 4700