EXPERIMENT 3 – DETERMINATION OF THE Keq

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When do you use this? You use Keq to find the concentration of a reversible reaction at equilibrium. You use Q to find the concentration of a reversible.

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Presentation transcript:

EXPERIMENT 3 – DETERMINATION OF THE Keq [Fe(NO3)3] 0.00100 M [KSCN] 0.000400 M [Fe3+]init 0.00100 M [SCN-]init 0.000400 M [FeSCN2+]init 0 M 5 5.00 2.00 3.00 EX3-1 (of 4)

EXPERIMENT 3 – DETERMINATION OF THE Keq Absorbance: 0.246 A = (3425 M-1)c - 0.021 0.246 = (3425 M-1)c - 0.021 0.267 = (3425 M-1)c 0.267 = c ___________ 3425 M-1 0.00007796 M = c = [FeSCN2+]eq EX3-2 (of 4)

EXPERIMENT 3 – DETERMINATION OF THE Keq Fe3+ (aq) + SCN- (aq) ⇆ FeSCN2+ (aq) Initial M’s Change in M’s Equilibrium M’s 0.00100 0.000400 - x - x + x 0.00100 - x 0.000400 - x x Kc = [FeSCN2+] _______________ [Fe3+][SCN-] Kc = x _________________________________ (0.00100 – x)(0.000400 – x) [FeSCN2+]eq = x = 0.00007796 M EX3-3 (of 4)

EXPERIMENT 3 – DETERMINATION OF THE Keq Fe3+ (aq) + SCN- (aq) ⇆ FeSCN2+ (aq) Initial M’s Change in M’s Equilibrium M’s 0.00100 0.000400 - x - x + x 0.00100 - x 0.000400 - x x Kc = [FeSCN2+] _______________ [Fe3+][SCN-] [Fe3+]eq = [SCN-]eq = [FeSCN-]eq = 0.00100 – x 0.000400 – x x = 0.000922 M = 0.0003220 M = 0.000077956 M x = 0.00007796 M Kc = (0.000077956 M) _________________________________ (0.000922 M)(0.0003220 M) = 260 M-1 EX3-4 (of 4)