By: Divya Lobo and Anshul Rangwani Apollo 13 By: Divya Lobo and Anshul Rangwani

What everything Represents X-axis: It represents the time Y-axis: Distance from the moon Equation: Y= 3x^2-78x+500 The graph is decreasing because the longer the time is the shorter the distance from the moon is y-intercept: (0,500) The y-intercept represents the original distance from the moon

Option 1 would be a disaster Reasons: Wasting fuel and high chance of death How did we find out if Apollo 13 went with option 1, they would die? If you were to graph the equation(3x^2-78x+500) it goes under the x-axis. As stated before, the x-axis is the moon, so if something hits the x-axis that means it hits the moon. It would be morally incorrect to let them try option one because there is a big chance of death

The steps in math (Calculator) The first thing we did, was plug in the points, so we can find the equation. The result was a= 3, b = -78, and c equals 500. We then created the equation 3x^2-78x+500, we graphed that and got this. ---------------------> To find where the rocket was at t=10 sec, we plugged 10 into our equation, and got 20 as a solution. Therefore, the rocket is at 20 km when t=10 sec.

Steps in Math Cont’d. 78/6 = 13 3(13^2)-78(13)+500 3(169)-78(13)+500 To find out the minimum point of the quadratic function you use the formula -b/2a and plug that into the equation. 78/6 = 13 3(13^2)-78(13)+500 3(169)-78(13)+500 507-1014+500 =-7 minimum point: (13,-7) Which therefore means that at 13 seconds, Apollo 13 is at its deepest point which is 7 km deep in the moon. To find out what time Apollo 13 would crash into the moon, you equate 3x^2- 78x+500 to 0, and used the quadratic formula. (78±√6084-6000)/6 (78 ±√84)/6 (78±9.17)/6 x= 14.528 or x=11.472 Apollo 13 crashes into the moon at 11.472 sec.