Lecture 6 Chemical Reaction Engineering (CRE) is the field that studies the rates and mechanisms of chemical reactions and the design of the reactors.

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Presentation transcript:

Lecture 6 Chemical Reaction Engineering (CRE) is the field that studies the rates and mechanisms of chemical reactions and the design of the reactors in which they take place.

Lecture 6 - Tuesday 1/25/2011 Block 1: Mole Balances Block 2: Rate Laws Block 3: Stoichiometry Block 4: Combine Review of Blocks 1, 2 and 3 Examples : Undergraduate Reactor Experiments CSTR PFR BR Gas Phase Reaction with Change in the Total Number of Moles

Building Block 1: Reactor Mole Balance in terms of conversion Previous Lectures Building Block 1: Reactor Mole Balance in terms of conversion Reactor Differential Algebraic Integral Batch X t CSTR PFR PBR X W

Building Block 2: Rate Laws Previous Lectures Building Block 2: Rate Laws Power Law Model A reactor follows an elementary rate law if the reaction orders just happens to agree with the stoichiometric coefficients for the reaction as written. e.g. If the above reaction follows an elementary rate law 2nd order in A, 1st order in B, overall third order

Previous Lectures Building Block 3: Stoichiometry

Block 4: Combine Previous Lectures

Block 4: Combine Previous Lectures

Today’s lecture Example for Liquid Phase Undergraduate Laboratory Experiment (CH2CO)2O + H2O  2CH3COOH A + B  2C Entering Volumetric flow rate v0 = 0.0033 dm3/s Acetic Anhydride 7.8% (1M) Water 92.2% (51.2M) Elementary with k’ 1.95x10-4 dm3/(mol.s) Case I CSTR V = 1dm3 Case II PFR V = 0.311 dm3

Today’s lecture 2NOCl  2NO + Cl2 2A  2B + C Example for Gas Phase : PFR and Batch Calculation 2NOCl  2NO + Cl2 2A  2B + C Pure NOCl fed with CNOCl,0 = 0.2 mol/dm3 follows an elementary rate law with k = 0.29 dm3/(mol.s) Case I PFR with v0 = 10 dm3/s Find space time, with X = 0.9 Find reactor volume, V for X = 0.9 Case II Batch constant volume Find the time, t, necessary to achieve 90% conversion. Compare and t.

Part 1: Mole Balances In Terms of Conversion Lecture 6 Part 1: Mole Balances In Terms of Conversion Algorithm for Isothermal Reactor Design Mole Balance and Design Equation Rate Law Stoichiometry Combine Evaluate A. Graphically (Chapter 2 plots) B. Numerical (Quadrature Formulas Chapter 2 and appendices) C. Analytical (Integral Tables in Appendix) D. Software Packages (Appendix- Polymath)

CSTR Laboratory Experiment Example: CH3CO2 + H20  2CH3OOH A + B  2C 1) Mole Balance:           CSTR:

CSTR Laboratory Experiment 2) Rate Law: 3) Stoichiometry: A FA0 -FA0X FA=FA0(1-X) B FA0ΘB -FA0X FB=FA0(ΘB-X) C 2FA0X FC=2FA0X

CSTR Laboratory Experiment

CSTR Laboratory Experiment

PFR Laboratory Experiment A + B  2C 1) Mole Balance: 2) Rate Law: 3) Stoichiometry:

PFR Laboratory Experiment 4) Combine:

Example (Gas Flow, PFR) 2 NOCl  2 NO + Cl2 2A  2B + C 1) Mole Balance: 2) Rate Law:

Example (Gas Flow, PFR) 3) Stoich: Gas A  B + ½C 4) Combine:

Example (Gas Flow, PFR)

Example Constant Volume (Batch) Gas Phase 2A  2B + C Example Constant Volume (Batch) 1) Mole Balance: 2) Rate Law: 3) Stoich: Gas, but:

Example Constant Volume (Batch) 4) Combine:

Heat Effects Isothermal Design Stoichiometry Rate Laws Mole Balance

End of Lecture 6