8.3 Quadratic Inequalities

A quadratic can be combined with inequalities If ax 2 + bx + c > 0 we are looking for values of x that makes the quadratic greater than zero If ax 2 + bx + c < 0, looking where the quadratic is less than zero Find intercepts –1.3 and 3.3 [–1.3, 3.3] Where is quadratic greater than or equal to 0? (above x-axis) Ex 1) Solve –2x 2 + 4x with the aid of a graph. *graph on TV*

We can also solve them algebraically without using a picture. Ex 2) Solve –x 2 – 4x algebraically x 2 + 4x – 5 0 (x + 5)(x – 1) 0 x = –5, 1 –5 1 Is the value (+) or (–)? (dont care about actual #) closed circles want (+) values Choose test points in each interval (–)(–) (+) (+)(–) (–) (+)(+) (+) (–, –5] [1, )

They dont always have to be integer answers. Ex 3) Solve 6x x – 5 0 algebraically cant factor – Want (–) quadratic formula! = 0.40 or –2.07 –3 54 – 30 – 5 (+) 0 –5 (–) – 5 (+) [–2.07, 0.40]

Ex 4) The NCAA Mens Basketball Rulebook states the height of the basket on a regulation court must be 10 ft. For a particular throw the height s of a basketball at any time t, in seconds, can be determined by the equation s = –16t t + 6. Determine for what values of t, to the nearest tenth of a second, the ball is higher than the basket. Express in interval notation. –16t t + 6 > 10 –16t t – 4 > Want (+) = 0.1 or – 4 (–) 1 – – 4 (+) 3 – – 4 (–) (0.1, 2.4)

We can also graph quadratic inequalities *Remember dotted line y < shade below or solid line y > shade above Ex 5) Graph in the coordinate plane 4 – y 5x 2 – 2x –y 5x 2 – 2x – 4 y –5x 2 + 2x + 4 Solid line A of S: x = Vertex: y-int: shade below (0, 4) *You can also use a test point to confirm such as (0, 0) 4 – 0 5(0) 2 – 2(0) 4 0 Yes include (0,0)

Homework #803 Pg 404 #1, 2, 5, 12, 13, 18, 19, 20, 22, 27, 31, 38, 42, 47