Chapter 15 Chemical Equilibrium Chemistry, The Central Science, 11th edition Theodore L. Brown; H. Eugene LeMay, Jr.; Bruce E. Bursten and Catherine J. Murphy Chapter 15 Chemical Equilibrium Donna Narsavage Heald Siena College Loudonville, NY  2009, Prentice-Hall

What is Kp in terms of Kc for the following reaction ? What is Kp in terms of Kc for the following reaction ? 2 NO(g) + O2(g) 2 NO2(g) Kp = KcRT Kp = Kc/RT Kp = KcR/T Kp = Kc Kp = Kc/(RT)2

What is Kp in terms of Kc for the following reaction ? What is Kp in terms of Kc for the following reaction ? 2 NO(g) + O2(g) 2 NO2(g) Kp = KcRT Kp = Kc/RT Kp = KcR/T Kp = Kc Kp = Kc/(RT)2

What is the correct equilibrium constant expression for the reaction: P4(s) + 6 Cl2(g) 4 PCl3(l)

What is the correct equilibrium constant expression for the reaction: P4(s) + 6 Cl2(g) 4 PCl3(l)

Which accurately reflects the changes in concentration that will occur if O2 is added to disturb the equilibrium? 2 NO(g) + O2(g) 2 NO2(g) [NO] [O2] 1. Increase 2. Decrease 3. 4. 5.

Which accurately reflects the changes in concentration that will occur if O2 is added to disturb the equilibrium? 2 NO(g) + O2(g) 2 NO2(g) [NO] [O2] [NO2] 1. Increase 2. Decrease 3. 4. 5.

PCl3(g) + Cl2(g) PCl5(g) DH° = –87.9 kJ/mol Which of the following will result in an equilibrium shift to the right? PCl3(g) + Cl2(g) PCl5(g) DH° = –87.9 kJ/mol Increase temperature/increase volume Increase temperature/decrease volume Decrease temperature/increase volume Decrease temperature/decrease volume None of the above PCl5

PCl3(g) + Cl2(g) PCl5(g) DH° = –87.9 kJ/mol Which of the following will result in an equilibrium shift to the right? PCl3(g) + Cl2(g) PCl5(g) DH° = –87.9 kJ/mol Increase temperature/increase volume Increase temperature/decrease volume Decrease temperature/increase volume Decrease temperature/decrease volume None of the above PCl5

What is the value of Kc for the reaction? What is the value of Kc for the reaction? 2 CO(g) + O2 (g) 2CO2(g) Kc = 5.0 x 1018 at 25 °C CO2(g) CO(g) + 1/2 O2(g) Kc = ?? at 25 °C Kc = 1/(5.0 x 1018)1/2 Kc = 1/(2.5 x 1018) Kc = –(5.0 x 1018)/2 Kc = –(5.0 x 1018)1/2 Kc = 2/(5.0 x 1018)1/2

What is the value of Kc for the reaction? What is the value of Kc for the reaction? 2 CO(g) + O2(g) 2 CO2(g) Kc = 5.0 x 1018 at 25 °C CO2(g) CO(g) + 1/2 O2(g) Kc = ?? at 25 °C Kc = 1/(5.0 x 1018)1/2 Kc = 1/(2.5 x 1018) Kc = –(5.0 x 1018)/2 Kc = –(5.0 x 1018)1/2 Kc = 2/(5.0 x 1018)1/2