Lesson 2 LT: I can explain phase change calculations in terms of heat absorbed and heat released.

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Presentation transcript:

Lesson 2 LT: I can explain phase change calculations in terms of heat absorbed and heat released.

You have 3 minutes to answer the following questions. Food For Thought You have 3 minutes to answer the following questions.

3 Minutes What mass of water can be heated from 25.0°C to 50.0°C by the addition of 2825 J?

2 Minutes What mass of water can be heated from 25.0°C to 50.0°C by the addition of 2825 J?

1 Minute What mass of water can be heated from 25.0°C to 50.0°C by the addition of 2825 J?

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LESSON 2 Food For Thought You have 3 minutes to answer the following question.

3 Minutes What heat equation would be used for each section of the heating curve?

2 Minutes What heat equation would be used for each section of the heating curve?

1 Minute What heat equation would be used for each section of the heating curve?

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LESSON 2 Food For Thought You have 3 minutes to answer the following question.

3 Minutes What is the change in enthalpy when 9.75 g of aluminum reacts with excess ammonium nitrate (NH4NO3) according to the equation: 2Al + 3NH4NO3  3N2+ 6 H2O + Al2O3 ΔH =-2030kJ

2 Minutes What is the change in enthalpy when 9.75 g of aluminum reacts with excess ammonium nitrate (NH4NO3) according to the equation: 2Al + 3NH4NO3  3N2+ 6 H2O + Al2O3 ΔH =-2030kJ

1 Minute What is the change in enthalpy when 9.75 g of aluminum reacts with excess ammonium nitrate (NH4NO3) according to the equation: 2Al + 3NH4NO3  3N2+ 6 H2O + Al2O3 ΔH =-2030kJ

10 Seconds

9 Seconds

8 Seconds

7 Seconds

6 Seconds

5 Seconds

4 Seconds

3 Seconds

2 Seconds

1 Second

Let’s get Started Feeding Your Mind!