Barium chloride reacts with sulfuric acid to produce barium sulfate and hydrochloric acid. If 98.2g of hydrochloric acid is needed how much barium chloride.

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Presentation transcript:

Barium chloride reacts with sulfuric acid to produce barium sulfate and hydrochloric acid. If 98.2g of hydrochloric acid is needed how much barium chloride should be used? If 62.5g of barium sulfate is needed, how much HCl is acid will also be produced?

BaCl2 + H2(SO4)  Ba(SO4) + 2HCl Barium chloride reacts with sulfuric acid to produce barium sulfate and hydrochloric acid. BaCl2 + H2(SO4)  Ba(SO4) + 2HCl

BaCl2 + H2(SO4)  Ba(SO4) + 2HCl If 98 BaCl2 + H2(SO4)  Ba(SO4) + 2HCl If 98.2g of hydrochloric acid is needed how many grams of barium chloride should be used?

BaCl2 + H2(SO4)  Ba(SO4) + 2HCl If 62 BaCl2 + H2(SO4)  Ba(SO4) + 2HCl If 62.5g of barium sulfate is needed, how much HCl is acid will also be produced?