Vectors Day 9 Lyzinski Physics
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Day #9
Plane Problems
Important things to know: P: Plane W: Wind G: Ground vPG = vPW + vWG “airspeed” means VPW You can use d = rt in these problems only because a = 0
vPG = vPW + vWG Example: A plane is flying with an airspeed of 400 mph in the northeast direction. Wind is blowing towards the North at 50 mph. Find the velocity of the plane relative to the ground. 45o 400 = + 282.84 50 = 436.8 49.6o VPG = 436.8 mph [E 49.6o N]
A difficult plane problem From tonight’s HW vPG = vPW + vWG vWG = vPG + -vPW rearranging 200 mph 10o 226.51 mph 230 mph 39.94 mph ??? x: y: Vx = -39.94 + 0 = -39.94 mph Putting together the super triangle yields VWG = 47.9 mph [W 33.6o N] Vy = 226.51 – 200 = 26.51 mph
Tonight’s HW Review for Test 2 night HW Assignment! Review for Test Days #9 & #10 Review For Test (from the packet) The Ultimate River Problem and the Ultimate Plane Problem (from the packet)