UNIT II RECIPROCAL EQUATIONS

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Presentation transcript:

UNIT II RECIPROCAL EQUATIONS Dr. T. VENKATESAN Assistant Professor Department of Statistics St. Joseph’s College, Trichy-2.

Mathematics Reciprocal Functions FACULY OF EDUCATION Department of Curriculum and Pedagogy Mathematics Reciprocal Functions Science and Mathematics Education Research Group Category: Secondary – Mathematics – Functions – Reciprocal Functions Tags: reciprocals, graphing Excerpt: This question set explains how the graph of a function changes when we take its reciprocal.

Reciprocal Functions

Reciprocal Functions This question set deals with functions in the form: Given the function f(x), we will analyze the shape of the graph of g(x). Notice the difference between the reciprocal of a function, and the inverse of a function: The reciprocal and the inverse of a function are not the same. Reciprocal: Inverse:

Reciprocal Functions I Consider the value of (the reciprocal of p) , where . Which of the following correctly describes the approximate value of for varying values of ? p is very large (for example, p = 1000) p is very small (for example, p = 0.0001) is large is close to 0

Solution Answer: B Justification: Fractions with large denominators are smaller than fractions with small denominators (for equal positive numerators). Consider when p = 1000. Its reciprocal is a very small positive number: As p becomes larger, its reciprocal becomes smaller. Now consider when p = 0.001. Its reciprocal is a number much greater than 1: As p becomes smaller, its reciprocal becomes larger.

Reciprocal Functions II Consider the function . When , what are the possible values for ? Exponent laws: Press for hint

Solution Answer: B Justification: Try choosing a value for , such as . In this case, Since , which is greater than 1, we can rule out C, D, and E. We must check if it is possible for to be between 0 and 1 in order to choose between answers A and B. Notice that is only between 0 and 1 when the numerator is smaller than the denominator. This is not possible, because the denominator is never greater than 1. Therefore, when .

Reciprocal Functions III Consider a function and its reciprocal function . Suppose that at , . What are all the possible values for ?

Solution Answer: D Justification: This question asks to find the values of f(p) where . We must find a value that is equal to its reciprocal. We can get the answer directly by solving the above equation for f(p): If we tried to plug in , we get which is undefined. Conclusion: Points where are also points on the reciprocal of f. Points where form vertical asymptotes on the reciprocal function. Notice:

Reciprocal Functions IV Let . Which of the following correctly describes when and when ?

Solution Answer: C Justification: When , must also be greater than zero. The numerator is positive, and the denominator is positive. A positive number divided by a positive number is positive. When , must also be less than zero. The numerator is positive but the denominator is negative. A positive number divided by a negative number is negative. Conclusion: If is above the x-axis, is also above the x-axis. When is below the x-axis, is also below the x-axis.

Reciprocal Functions V If the point , where , lies on the graph of , what point lies on the graph of ? Notice that this question has the restriction that b ≠ 0. What would happen to the point on the reciprocal function if b = 0?

Solution Answer: C Justification: The reciprocal function takes the reciprocal of the y-value for each point in . Consider when x = a: Notice that x-values are not changed. The point transforms into the point . Do not get confused with the inverse of a function , which interchanges x and y-values. In general: when x = a since f(a) = b

Summary

Strategy for Graphing I Consider the function and its reciprocal function . The following example outlines the steps to graph : Identify the points where or . These points exist on the reciprocal function. (See question 3)

Strategy for Graphing II Identify the points where . Draw a dotted vertical line through these points to show the locations of the vertical asymptotes. (Recall taking the reciprocal of 0 gives an undefined value.)

Strategy for Graphing III Consider when . Draw a curve from the top of the asymptote line to the point where . When , draw the curve from the bottom of the asymptote to . The reciprocal of small values become large values.

Strategy for Graphing IV Consider where . From the point , draw a curve that approaches the x-axis from above. When , the curve approaches the x-axis from below. The reciprocal of large values become small values.

Strategy for Graphing V The final graph of is shown below.

Reciprocal Functions VI B. The graph of is shown below. What is the correct graph of its reciprocal function, ? C. D.

Solution Answer: D Justification: Since , its reciprocal must also pass through the point (1,1). This eliminates answers B and C. Additionally, f is positive for and negative for . This must also be true for the reciprocal function, so answer A must be eliminated because it is always positive. The only remaining answer is D. What other features can be used to identify the reciprocal function? What can we say about points (1,1) and ?

Reciprocal Functions VII B. The graph of is shown below. What is the correct graph of its reciprocal function, ? C. D.

Solution Answer: A Justification: When , . The reciprocal function also has this horizontal line since the reciprocal of 1 is still 1. This eliminates answers B and D. Since f(0) = 0, g(x) must have an asymptote at x = 0. This only leaves function A. Also notice that both f and g share the point (2,-1). Recall that all points on the lines y = -1 and y = 1 lie on both functions f and g.

Reciprocal Functions VIII B. The graph of is shown below. What is the correct graph of its reciprocal function, ? C. D.

Solution Answer: C Justification: Consider the point (0, 2) on . This point will appear as on . Only function C passes through this point. What other features can be used to identify the reciprocal function? Notice that reciprocal function g has asymptotes at x = -2 and x = 2. This is where the function x crosses the x-axis. The functions g and f also intersect at the lines y = -1 and y = 1, since taking the reciprocal at these values do not change.

Reciprocal Functions IX B. The graph of is shown below. What is the correct graph of its reciprocal function, ? C. D.

Solution Answer: A Justification: The reciprocal function must be positive when the original function is positive, and negative when the original function is negative. This eliminates answers B and D. The reciprocal function must have asymptotes at because the original function has zeroes at these values of x. Only graph A satisfies both of these conditions.

Reciprocal Functions X B. What is the graph of the reciprocal function C. D.

Solution Answer: D Justification: Find where the original function crosses the lines : passes through the point (1, -1). has an asymptote at x = 0.5. passes through the point (0, 1). Only graph D satisfies these 3 conditions. This question can also be solved by first graphing , then determining the reciprocal graph.

Reciprocal Functions XI The graph shown to the right is in the form: What are the values of m and b?

Solution Answer: C Justification: The function f is in the form . We need to find a pair of points that lie on f to determine its equation. One good choice is (-4, 1) and (0, -1), since these points lie on both f and f-1. Another choice for a point is (-2, 0), since there is an asymptote at x = -2. Using any of the 3 points mentioned above, find the slope of the line: The y-intercept is at (0, -1), so Points that lie on the green lines belong to both f and its reciprocal

Reciprocal Functions XII B. What is the graph of the cotangent function? C. D.

Solution Answer: B Justification: The points that lie on both the tangent and cotangent function are and . The tangent function also has asymptotes at , where k is an integer. At these values of x, the cotangent function must return 0. The cotangent function has asymptotes at x = kπ.