Lecture 11 Chemical Reaction Engineering (CRE) is the field that studies the rates and mechanisms of chemical reactions and the design of the reactors.

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Presentation transcript:

Lecture 11 Chemical Reaction Engineering (CRE) is the field that studies the rates and mechanisms of chemical reactions and the design of the reactors in which they take place.

Lecture 11 – Thursday 2/10/2011 Determining the Rate Law from Experimental Data Integral Method Differential (Graphical) Method Nonlinear Least Regression

Integral Method Mole Balance: Rate Law: Stochiometry: Combine: Consider the following reaction that occurs in a constant volume Batch Reactor: (We will withdraw samples and record the concentration of A as a function of time.) A  Products Mole Balance: Rate Law: Stochiometry: Combine:

Finally we should also use the formula to plot reaction rate data in terms of conversion vs. time for 0, 1st and 2nd order reactions. Derivation Equations used to Plot 0, 1st and 2nd order reactions. These types of plots are usually used to determine the values k for runs at various temperatures and then used to determine the activation energy. Zero order First Order Second Order

Finding the Rate law (Integral Method) Guess and check for α = 0, 1, 2 and check against experimental plot t CA ln(CA0/CA) 1/CA

Differential Method Slope = α Taking the natural log of The reaction order can be found from a ln-ln plot of: ln Slope = α ln

concentration (moles/dm3) CA0 CA1 CA2 CA3 Methods for finding the slope of log-log and semi-log graph papers may be found at http://www.physics.uoguelph.ca/tutorials/GLP/. However, we are usually given concentration as a function of time from batch reactor experiments: time (s) t1 t2 t3 concentration (moles/dm3) CA0 CA1 CA2 CA3

Three Ways to determine (-dCA/dt) from Concentration-Time Data Graphical differentiation Numerical differentiation formulas Differentiation of a polynomial fit to the data 1. Graphical

The method accentuates measurement error!

Example - Finding Rate Law t(min) 1 2 3 CA(mol/L) 0.7 0.5 0.35 0.3 0.2 0.15 .1 .2 .3 t 1 2 3 Areas equal for both sides of the histogram

Example - Finding Rate Law Find the f(t) of using equal area differentiation CA 1 0.7 0.5 0.35 -dCA/dt 0.25 0.175 0.12 Plot (–dCA/dt) as a function of CA ln CA Slope = α dCA/dt

Non-Linear Least-Square Analysis We want to find the parameter values (α, k, E) for which the sum of the squares of the differences, the measured rate (rm), and the calculated rate (rc) is a minimum. That is, we want to be a minimum.

Non-Linear Least-Square Analysis For concentration-time data, we can combine the mole balance equation for to obtain

Regression Method Guess values for α and k and solve for measured data points then sum squared differences: Cmeas 1 0.7 0.5 0.35 CCalc 0.33 0.25 (Cc-Cm) -0.2 -0.17 -0.10 (Cc-Cm)2 0.04 0.029 0.01 0.07 for α= 2, k = 1 → S2 = 0.07 for α = 2, k = 2 → S2 = 0.27 etc. until S2 is a minimum

Non-Linear Least-Square Analysis We find the values of alpha and k which minimize s2

Residuals

End of Lecture 11