Adding subtracting binomial

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Presentation transcript:

Adding subtracting binomial using multiplication

Example1: Add 2x(x + 3) and 3x(x + 5) Solution Step1:- Use distributive property to open the parenthesis. [2x(x + 3)] + [3x(x + 5)] = [(2x x x) + (2x x 3)] + [(3x x x)+(3x x 5)] = [2x2 + 6x] + [3x2 + 15x] = 2x2 + 6x + 3x2 + 15x (after removing the bracket) Step2:- Combine all the like terms = 2x2 + 3x2 + 6x + 15x (after rearranging the terms) = 5x2 + 21x (combining like terms)

Example2: Subtract 5y(2y - 5) and 2y(3y - 7) Solution Step1:- Use distributive property to open the parenthesis. [5y(2y - 5)] - [2y(3y - 7)] = [(5y x 2y) + (5y x -5)] - [(2y x 3y)+(2y x -7)] = [10y2 – 25y] - [6y2 - 14y] If negative sign outside bracket then reverse the sign of each term inside the bracket = 10y2 – 25y - 6y2 + 14y (after removing the bracket) Step2:- Combine all the like terms = 10y2 - 6y2 - 25y + 14y (after rearranging the terms) = 4y2 – 11y (combining like terms)

Try these Add 2m(m + 3) and 3m(m - 5) Subtract 3p(p - 5) and 2p(p + 3)