LO: I know how to write redox equations.

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Presentation transcript:

LO: I know how to write redox equations.

A redox equation is formed by joining two ion-electron equations: An equation (top) oxidation A equation (bottom) reduction Before combining they must be balanced for electrons. 2 Na Na+ + e- 2 2 F2 + 2e- 2F- 2Na + F2 2Na+ + 2F- LO: I know how to write redox equations.

2MnO4-+ 5SO32-+ 6H+ 2Mn2++ 5SO42-+ 3H2O Example 2: 5 SO32- + H2O SO42- + H+ + e- 5 5 10 2 10 2 2 MnO4-+ H+ + e- Mn2+ + H2O 16 8 10 5 2 8 4 2MnO4-+ 5SO32-+ 6H+ 2Mn2++ 5SO42-+ 3H2O LO: I know how to write redox equations.

11.2.2 Ion-electron equations from scratch LO: I know how to write ion-electron equations from scratch.

What is the ion-electron equation for the reduction of acidified dichromate ions, Cr2O72-(aq), to chromium (III) ions, Cr3+(aq), in aqueous solution? LO: I know how to write ion-electron equations from scratch.

1. Balance the non-oxygen element: Cr2O72-(aq) Cr3+(aq) 2 2. Balance oxygen using water: 2 Cr2O72-(aq) Cr3+(aq) + 7H2O(l) 3. Balance hydrogen using H+(aq) ions: 2 Cr2O72-(aq) Cr3+(aq) + 7H2O(l) + 14H+(aq) 4. Balance charge using electrons: 2 Cr2O72-(aq) Cr3+(aq) + 7H2O(l) + 14H+(aq) + 6e- LO: I know how to write ion-electron equations from scratch.