Bell Ringer 1-5 Reading Quiz

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Presentation transcript:

Bell Ringer 1-5 Reading Quiz 10-17 03 1. What is the Title of Lesson 1-5? 2. What is an open sentence? 3. What is the purpose of a replacement set? 4. What are the three types of solutions that are possible? 5. What does “to solve an equation” mean?

Lesson 1-5 Equations Objectives: By the end of class, students will be able to: Find the solution set for various replacement sets Solve equations with one or two variables with 90% or above mastery.

p. 33 A mathematical statement that has algebraic expressions is called an open sentence . A sentence that has an equals sign, =, is called an equation. 3a + 7  expression 3a + 7 = 16  equation Find the value of a variable that makes a sentence true is called solving the open sentence. This replacement value is called the solution.

A set of numbers that replace the variable are called a replacement set. A set is a collection of numbers or objects that is often shown using braces. Each object in the set is called an element. A solution set is the set of numbers that make the equation true.

p. 36 3. 29 = 3x – 7 Replacement set {11, 12, 13, 14, 15} The solution set is {12}. x 29 = 3x – 7 Answer True or False 11 12 13 14 15

Example: 28 = 4(1 + 3d) Replacement set = {0,1, 2, 3} The solution set is {2} d 28 = 4(1 + 3d) Answer True or False 1 2 3

33. School: Important Facts Conference room holds a maximum of 85 people. The principal and 2 counselors need to meet with juniors to discuss college admissions. Each student must bring a parent. Assume that each student has a unique set of parents. Question How many students can attend the meeting? Let s = the number of students that can attend.

s = 85 – 3 2 s = 82 s = 41 41 students can attend the meeting. 2s + 3 = 85 - 3 -3 2s = 82 2 2 s = 41 41 students can attend the meeting.

45. c + (32 - 3) = 21 c + (9 – 3) = 21 Parenthesis - Exponents c + 6 = 21 Parentheses - Subtract -6 -6 Subtract 6 on both sides c = 15

p. 37 #61 Geometry: Important Facts: The length of a rectangle is 2 inches greater than the width. The length of the base of an isosceles triangle is 12 inches. The lengths of the other 2 sides are 1 inch greater than the width of the rectangle. a. Draw a picture of each figure and label the dimensions.

b. Write two expressions to find the perimeters of the rectangle and triangle. c. Find the width of the rectangle if the perimeters of the figures are equal.

Lesson 2-2 Solving One-Step Equations Objectives: By the end of class, students will be able to: Solve one-step equations using addition and subtraction Solve one-step equations using multiplication and division. with 90% or above mastery.

p. 86 To solve an equation means to find the value of the variable that makes the equation true. In order to solve equations, you must undo (work backwards) the order of operations. 1. g + 5 = 33 - 5 - 5 Subtract 5 on both sides g = 28 4. -4 + t = -7 t – 4 = -7 +4 +4 Add 4 on both sides t = -3

Ex. Like 20. -45 = a + (-6) -45 = a – 6 +6 +6 Add 6 on both sides -39 = a 10. t = -5 7 (7) t = -5(7) Multiply both sides by 7 t = -35

p. 87 56. Six times a number is 132. Find the number. 6n = 132 6 6 Divide both sides by 6 n = 22 68. Cameras: Important Facts The camera is $126. This is 2/3 of the price that a photography store charges. What is the cost of the camera at the photography store?

126 = 2 c 3 3 ● 126 = 2 c ● 3 Multiply the reciprocal on 2 3 2 both sides 378 = c 2 189 = c The cost of the camera is $189.

Exit Slip 1. p. 36 #15 2. p. 86 #5