Brentwood CalcuSolve 2012 2012 Brentwood CalcuSolve

Good Morning and Welcome to the Brentwood 2012 CalcuSolve Competition! We hope you have a challenging and successful day! While we are waiting for all the teams to arrive, please: 1. Sit at the table to which you were assigned. 2. Make a nametag. Include your first and last name, school name, and team letter on the tag. Please wear the nametag during the entire competition. 3. Each person on your team should take one stapled packet of individual answer sheets and complete all the information on EVERY sheet. Print neatly! Your team letter is displayed on the sign at your table. Begin to practice for the competition by working on the Math Brain Warm-ups that are in your folder. If you need help or further direction, please find a Brentwood Ambassador or see Ms. Klousnitzer, Ms.Flaherty, or Mr.Sundo. Relax, Have Fun, and Good Luck! 2012 Brentwood CalcuSolve

SCORING There will be seven Individual Questions. You will be given 5 minutes to earn 5 points for a correct answer on each Individual Question. OR You may wait for a clue, work an extra 2 minutes and earn 3 points for a correct answer on each Individual Question. There will be two Group Questions. Your team of students will be given 7 minutes to earn 10 points for a correct answer on each Group Question. 2012 Brentwood CalcuSolve

Group Question – Round #1 During Lena’s basketball season, her team won 2/3 of their games, tied 1/8 of the games, and lost the rest. If they lost 5 games, how many games do they play each season? 2012 Brentwood CalcuSolve

Group Question – Round #1 Solution Lena’s team won 2/3 of their games, tied 1/8 of the games, and lost the rest which was 5 games. Use a common denominator to find the fraction for losses. Common denominator for the two given fractions is 24. 2/3 becomes 16/24=16 wins 1/8 becomes 3/24=3 wins 5 losses is 5/24 16+3+5= They played 24 games. 2012 Brentwood CalcuSolve

Individual Question – Round #2 Question Margo has 723 pennies. Jordan has 1/3 the number of pennies Margo has. Lincoln has twice as man pennies as Jordan. How many pennies do the three students have altogether? 2012 Brentwood CalcuSolve

Individual Question – Round #2 Hint Jordan and Lincoln both have less pennies than Margo. 2012 Brentwood CalcuSolve

Individual Question – Round #2 Solution 1,446 pennies Margo has 723 pennies Jordan has 241 pennies= 723 X 1/3 Lincoln has 482 pennies= 241 X 2 723+241+482=1,446 2012 Brentwood CalcuSolve

Individual Question – Round #3 Question Today is Saturday. What day will it be 200 days from today? 2012 Brentwood CalcuSolve

Individual Question – Round #3 Hint 105 days from today is also Saturday. 2012 Brentwood CalcuSolve

Individual Question – Round #3 Solution Today is Saturday. Every 7 days will be a Saturday. 200 ÷ 7=28 28 X 7=196 The 196th day is Saturday. 200-196=4 4 days from Saturday is Wednesday 2012 Brentwood CalcuSolve

Individual Question – Round #4 Question Lauren put 5/8 of the money she earned babysitting in her savings account. She spend 1/3 of the remaining money on new shoes. She had $30 left. How much money did she earn babysitting? 2012 Brentwood CalcuSolve

Individual Question – Round #4 Hint Lauren earned less than $200. 2012 Brentwood CalcuSolve

Individual Question – Round # 4 Solution Lauren put 5/8 of her money in savings. She spent 1/3 of the remaining money. She had $30 left after buying shoes. Remaining Money =$45 $30= 2/3, $15=1/3 $45=3/8 of her babysitting money $75=5/8 which is the money out in savings 75+45= She earned $120 2012 Brentwood CalcuSolve

Individual Question – Round # 5 Question Juan and Leah were playing at the park and counted the people they saw. There were 5 kids for every 2 adults. If there were a total of 147 people at the park, how many of them were kids? 2012 Brentwood CalcuSolve

Individual Question – Round # 5 Hint There were more than 100 kids at the park. 2012 Brentwood CalcuSolve

Individual Question – Round # 5 Solution There were 5 kids for every 2 adults. There were a total of 147 people in the park. 5+2 = 7 147÷ 7= 21 21 X 5= 105 kids in the park 2012 Brentwood CalcuSolve

Individual Question – Round # 6 Question James and Jake put their birthday money together to buy some video games and DVDs. A video game costs $15 more than a DVD. James and Jake spent $213 on 3 video games and 3 DVDs. How much does 1 DVD cost? 2012 Brentwood CalcuSolve

Individual Question – Round # 6 Hint 1 DVD and 2 video games would cost $99. 2012 Brentwood CalcuSolve

Individual Question – Round # 6 Solution A video game costs $15 more than a DVD. They spent $213 on 3 video games and 3 DVDs. DVD= x Video game= x+15 3x+45 +3x=213 6x=168 x=28 One DVD cost $28. 2012 Brentwood CalcuSolve

Individual Question – Round # 7 Question Dylan is older than 20, but younger than 50. This year, you can count by 3s to reach Dylan’s age. In two years, you will be able to count by 5s to reach Dylan’s age. In four years, Dylan’s age will be a prime number. How old is Dylan now? 2012 Brentwood CalcuSolve

Individual Question – Round # 7 Hint Dylan is not 28 years old. 2012 Brentwood CalcuSolve

Individual Question – Round # 7 Solution This year, you can count by 3s to reach Dylan’s age. Older than 20, but younger than 50. 21, 24, 27, 30, 33, 36, 39, 42, 45, 48 In two years, you will be able to count by 5s to reach Dylan’s age. In four years, Dylan’s age will be a prime number. 33, 48 Dylan is 33 years old. 2012 Brentwood CalcuSolve

Individual Question – Round # 8 Question This year, 50 students competed in the Geography Bee. During the first round, 20% of the competitors were eliminated. In the second round, 50% of the remaining competitors were eliminated. During the third round, 20% of the remaining competitors were eliminated. How many students were left to start the fourth round? 2012 Brentwood CalcuSolve

Individual Question – Round # 8 Hint 10 students were eliminated in the first round. 2012 Brentwood CalcuSolve

Individual Question – Round # 8 Solution 50 X 20%=10 50-10=40 Round 2 40 X 50%=20 40-20=20 Round 3 20 X 20%=4 20-4=16 16 students were left to start the 4th round. 2012 Brentwood CalcuSolve

Group Question – Round # 9 A computer password must be made up of 4 characters: letters from A – Z and/or numbers from 0-9. The first character must be a letter; the remaining three characters can be a letter or number. Each number and letter may only be used once. How many different password combinations are possible? 2012 Brentwood CalcuSolve

Group Question – Round # 9 Solution A computer password must be made up of 4 characters. : letters from A – Z and/or numbers from 0-9. The first character must be a letter. 26 The remaining three characters can be a letter or number. Each number and letter may only be used once. The second character. 35 (26+10-1) The third character 34 (35-1) The fourth character 33 (34-1) 26 x 35 x 34 x 33= 1,021,020 2012 Brentwood CalcuSolve