Question 1 03 - C Force and Motion 20001 F F m F F m d d

Slides:



Advertisements
Similar presentations
Newton’s Laws June 5, 2012.
Advertisements

Lets Practice Drawing FBD’s and Solving Problems
No Strings Attached: Normal Forces, Force Vectors, Strings, Springs and Pulleys Chapter Important Vocabulary: Normal Force Contact Force Tension.
Newton’s Laws of Motion and Free Body Analysis
Forces & Motion answers
Phy100: More on Energy conservation Mechanical energy (review); Goals: Work done by external forces; Understand conservation law for isolated systems.
Newton’s Laws of Motion Problems MC Questions
T101Q7. A spring is compressed a distance of h = 9.80 cm from its relaxed position and a 2.00 kg block is put on top of it (Figure 3). What is the maximum.
Mechanical Energy and Simple Harmonic Oscillator 8.01 Week 09D
EVERY-DAY FORCES Force of gravity Normal force Force of friction Universal force of gravity.
Chapter 5 Newton’s Second Law of Motion – Force and Acceleration
Kinetic energy Derivation of kinetic energy. Kinetic Energy 2 starting equations F = m x a (Newton’s 2 nd law) W = Force x distance.
Newton’s Laws - continued Friction, Inclined Planes, N.T.L., Law of Gravitation.
Choose a category. You will be given the answer. You must give the correct question. Click to begin.
FORCE. A FORCE IS A PUSH OR A PULL. IF FORCES ARE POWERFUL ENOUGH, THEY MAY RESULT IN MOTION.  What is a force?
1 Some application & Forces of Friction. 2 Example: When two objects of unequal mass are hung vertically over a frictionless pulley of negligible mass,
Measurement and Motion Force Force is a kind of push or a pull on an object.
Exploring Frictional Forces Friction Friction and Newton’s Laws Static and Kinetic Friction Coefficient of Friction Practice.
Work, Energy, and Energy Conservation Chapter 5, Sections Pg
Friction Ffriction = μFNormal.
Friction What is friction?. Answer Me!!! Think of two factors that affect friction.
1 Motion – Newton’s Laws 1. Every body continues in its state of rest or uniform motion unless it is acted upon by a net external force. 2. The acceleration.
Power is the rate at which work is done.
Physics 1D03 - Lecture 81 Newton’s Laws (III) Blocks on ramps, and other problems Serway and Jewett : 5.7, 5.8.
Multiple Object Systems 1. Analyze the system as one object. 2. Analyze each object individually. 3. Create multiple equations to solve for multiple unknowns.
 Friction – force that opposes motion  Caused by microscopic irregularities of a surface  The friction force is the force exerted by a surface as an.
Physics 1D03 - Lecture 19 Kinetic Energy. Physics 1D03 - Lecture 19 Then the Work-Energy Theorem says: The total work done by all external forces acting.
Newton’s 2 nd Law Example with Angles! Consider a box of mass m being pulled across a rough horizontal floor with an applied force F A at 35 °. The coefficient.
Aristotle 384 – 322 BC ISAAC NEWTON.
Chapter 12: Matter in Motion. Reference Point An object that appears to stay in place that helps detect motion.
Fall 2011 PHYS 172: Modern Mechanics Lecture 7 – Speed of Sound in a Solid, Buoyancy Read 4.9 – 4.13.
Friction. I. Friction A. Background 1. A force that acts opposite the direction of movement 2. Friction slows you down and causes heat.
Chapter 4.1 Notes Resistance (is futile!). ► Newton’s 1st law - Every object in motion stays in motion; Every object at rest stays at rest unless acted.
NEWTON'S LAWS OF MOTION Philosophiae Naturalis Principia Mathematica (1686)
ENGINEERING PHYSICS SEMESTER /2012. ENGINEERING PHYSICS SUB-CHAPTERS: ● Work and standard units ● Power concept & Power Calculation ● Kinetic energy.
Newton’s First Law of Motion
Physics 11 Mr. Jean March 22nd, 2012.
Test Review Dynamics.
Today Finish Newton’s Laws More Forces.
Atwood Machines and Multiple Body Systems
Work and Power Quiz Solutions
PHYS 1443 – Section 002 Lecture #12
Force and Motion PHYSICS HONORS Lecture Notes
Newton’s Laws Acceleration
Friction Newton’s 2nd Law with Friction Examples Outline.
Aim: How do we explain the force of friction?
Forces.
Compound Body Problems
More Friction.
Force and Motion Physics 2053 Lecture Notes
Contact Friction Forces:
Today Finish Newton’s Laws More Forces.
BELL RINGER If I need to push something with a mass of 45kg at an acceleration of 5 m/s/s, what force would I have to apply? If I have a force of 5N pulling.
Ch. 5 slides Forces.ppt.
Forces of Friction When an object is in motion on a surface or through a viscous medium, there will be a resistance to the motion This is due to the interactions.
PHYS 1443 – Section 003 Lecture #12
Newton’s 2nd law Problems
Work and Power.
Newton’s Laws - continued
Potential Energy Problems
Sect. 7.5: Kinetic Energy Work-Kinetic Energy Theorem
Aim: How do we explain the force of friction?
Dynamics III Friction and Inclines.
How does an inclined plane make work easier How does an inclined plane make work easier? How does it change the force that is applied to the inclined.
Motion and Forces.
A block of mass m resting on a horizontal
Contact Friction Forces:
Forces on m1 N T m1 m1g T m2 m2g Forces on m2.
Forces on m1 N T m1 m1g T m2 m2g Forces on m2
Simple applications Of 1st & 2nd Laws.
Presentation transcript:

Question 1 03 - C Force and Motion 20001 F F m F F m d d A block of mass m initially at rest on a horizontal frictionless surface is pulled by a constant horizontal force F. The speed of the block after being pulled a distance d. A block of mass m initially at rest on a horizontal frictionless surface is pulled by a constant horizontal force F. The speed of the block after being pulled a distance d. Solution The constant force produces a constant acceleration Newton’s second law vo = 0 x = d F d m v 1

Solution... The final speed of the block vf F F m x Force and Motion 20001 Solution... vf F F F F m m d A block of mass m initially at rest on a horizontal frictionless surface is pulled by a constant horizontal force F. The speed of the block after being pulled a distance d. x The constant force produces a constant acceleration Newton’s second law Solution F d m v The constant force produces a constant acceleration Newton’s second law vo = 0 x = d

Question 2 03 - C Force and Motion 20005 F F F m m A block of mass m initially at rest on a horizontal frictionless surface is pulled by a constant horizontal force F. The speed of the block after being pulled for a time t is. A block of mass m initially at rest on a horizontal frictionless surface is pulled by a constant horizontal force F. The speed of the block after being pulled for a time t is. Solution The constant force produces a constant acceleration Newton’s second law vo = 0 F m 2

Solution... The final speed of the block vf F F m Force and Motion 20005 Solution... vf F m F F m A block of mass m initially at rest on a horizontal frictionless surface is pulled by a constant horizontal force F. The speed of the block after being pulled for a time t is. The constant force produces a constant acceleration Newton’s second law Solution The constant force produces a constant acceleration Newton’s second law vo = 0 F m

Question 3 03 - C Force and Motion 20009 F m F m A block of mass m initially at rest on a horizontal frictionless surface is pulled by a constant horizontal force F. The distance the block moves during a time t is A block of mass m initially at rest on a horizontal frictionless surface is pulled by a constant horizontal force F. The distance the block moves during a time t is Solution The constant force produces a constant acceleration Newton’s second law vo = 0 xo = 0 F m 3

Solution... Distance the block moves F m The constant force produces a Force and Motion 20009 Solution... F m F m A block of mass m initially at rest on a horizontal frictionless surface is pulled by a constant horizontal force F. The distance the block moves during a time t is The constant force produces a constant acceleration Newton’s second law Solution F m The constant force produces a constant acceleration Newton’s second law xo = 0 vo = 0

Question 4 03 - C Force and Motion 20012 vo v = 0 m m vo v = 0 A block of mass m initially moving with a speed vo slides horizontally across the surface before coming to rest. The coefficient of kinetic friction between the block and the surface is mk. The time required for the block to come to rest is A block of mass m initially moving with a speed vo slides horizontally across the surface before coming to rest. The coefficient of kinetic friction between the block and the surface is mk. The time required for the block to come to rest is Solution Newton’s second law SF = - f The constant frictional force produces a constant acceleration. v = 0 Frictional force: m vo 4

The constant frictional constant acceleration. Time required for the block to stop 03 - C Force and Motion 20012 Solution... vo v = 0 m m vo v = 0 The constant frictional force produces a constant acceleration. A block of mass m initially moving with a speed vo slides horizontally across the surface before coming to rest. The coefficient of kinetic friction between the block and the surface is mk. The time required for the block to come to rest is Frictional force: Newton’s 2nd law Solution m vo v = 0 The constant frictional force produces a constant acceleration. Newton’s second law Frictional force: SF = - f v = 0

Question 5 03 - C Force and Motion 20015 m vo v = 0 d vo v = 0 m d A block of mass m given an initial speed vo slides across a horizontal surface for a distance d before coming to rest. The coefficient of kinetic friction between the block and the surface is A block of mass m given an initial speed vo slides across a horizontal surface for a distance d before coming to rest. The coefficient of kinetic friction between the block and the surface is Solution Newton’s second law SF = - f The constant frictional force produces a constant acceleration. v = 0 Frictional force: x = d m vo d 5

The constant frictional constant acceleration. The coefficient of kinetic friction 03 - C Force and Motion 20015 Solution... m vo v = 0 d vo v = 0 m d A block of mass m given an initial speed vo slides across a horizontal surface for a distance d before coming to rest. The coefficient of kinetic friction between the block and the surface is The constant frictional force produces a constant acceleration. Frictional force: Newton’s 2nd law Solution m vo v = 0 d The constant frictional force produces a constant acceleration. Newton’s second law Frictional force: SF = - f v = 0 x = d

Question 6 03 - C Force and Motion 20017 F d m F d m A block of mass m initially at rest on a horizontal frictionless surface is pulled by a constant horizontal force F. The force is applied through a distance d and the block acquires a final speed v. If the applied force had been doubled (2F) the blocks final speed would have been A block of mass m initially at rest on a horizontal frictionless surface is pulled by a constant horizontal force F. The force is applied through a distance d and the block acquires a final speed v. If the applied force had been doubled (2F) the blocks final speed would have been Solution Newton’s second law The constant accelerating force produces a constant acceleration. vo = 0 x = d vx is the speed acquired when accelerating force is 2F F d m 6

Solution... The blocks final speed F m d The constant accelerating force produces a constant acceleration. Newton’s second law