6-2 Substitution Again Goals: Solve linear systems using substitution Interpret solutions to special problems Eligible Content: A1.1.2.2.1 / A1.1.2.2.2
Practice Complete worksheet – “Monstrous Mammal”
Special Problems No solution Many solutions There is no point in common All variables will cancel out You will be left with a false statement: 4 = 12 Many solutions There are many points in common You will be left with a true statement: 5 = 5
Examples 3x + y = –1 –9x – 3y = 3 many solutions x – 2y = 5 no solution 4x + 4y = –8 x + y = –2 many solutions 2x + y = –1 –6x – 3y = –15 no solution
Practice (not all problems are special) x – 2y = 1 –2x + 4y = 10 x – 3y = –24 5x + 8y = –5 6x + y = 14 12x + 2y = 28 No solution (-9, 5) Many solutions
Homework Page 347 #14-19