Homework: pg. 276 #5, 6 5.) A. The relationship is strong, negative, and curved. The ratios are all 0.717. Since the ratios are all the same, the exponential growth model is appropriate. Yes. The scatterplot shows that the transformation achieves linearity. ln (light)=6.7891-0.3330(depth). The intercept 6.7891 provides an estimate for the average value of the natural log of the light intensity at the surface of the lake. The slope, -0.3330 indicates that the natural log of the light intensity decreases by 0.3330 for each one meter increase in depth. The plot shows that the linear model on the transformed data is appropriate. The equation is: The predicted light intensity is 0.5846, very close to the observed light intensity.
Homework: pg. 276 #5, 6 6.) A. The model would be: 10-1094.51 would be zero so all predicted values would be zero. F. The ratios are 3.5890, 4.0090, and 3.1156 The residual plot shows no clear pattern so the transformed linear model is appropriate. C. H. I. The predicted number would be 10,722,597.42 acres Yes, this is correct.
4.1 Power Law Model
Algebra you need to know: Plus everything we talked about yesterday!!!
Power Law Model power law model: numbers
Alligator Data Length Weight 94 130 86 83 74 51 88 70 147 640 72 61 58 28 54 80 44 110 90 106 63 33 89 84 68 39 69 36 76 42 38 114 197 128 366 102 85 78 57 82
Alligator Data Make a scatterplot—what is the pattern? Take the log of both the x and the y variables What is the equation of the LSRL?
Boyle’s Law Volume Pressure 6 2.9589 8 2.4073 10 1.9905 12 1.7249 14 1.5288 16 1.3490 18 1.2223 20 1.1201 1. Make scatterplot—what is the pattern? 2. Take ln of both x and y variables. What is your equation of the line?
HW: pg 285 #11-12 pg 289 #16