The Mirror Equation and Ray Diagrams.

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Presentation transcript:

The Mirror Equation and Ray Diagrams

object distance image distance focal length

I look in a mirror with a focal length of 20 cm at arms length, 70 cm away. Where would the image of my eyeball form? Is it real or virtual? f = .2 m 1/p + 1/q = 1/f p = .7 m 1/q = 1/f – 1/p 1/q = 1/.2m – 1/.7m 1/q = 3.57 m-1 q = .28 m A real image… it is positive

Ray Diagrams f = .2m C = .4m 1. Parallel rays go thru f 2. Thru f goes parallel 3. Thru C bounces back

q = 4 m ? f = 10 m C = 20 m p = 3 m 1/f - 1/p = 1/q 1/10 m- 1/3m = - .2333 m-1 q = -4.29