Basic Math Review for Relay Techs

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Presentation transcript:

Basic Math Review for Relay Techs Bill Unbehaun Tacoma Power

Triangle Basics Pythagorean Theorem 1000 1800 450 350 300 600 600 600 3.7 3.7 10 10 600 600 750 750 3.7 Equilateral Isosceles

30-60-90 Right Triangle Basic Trigonometry: SOH – Sine = Opposite over hypotenuse CAH – Cosine = Adjacent over hypotenuse TOA – Tangent = Opposite over adjacent 60 600 1 0.5 30 900 300 0.866

1200 and √3 120 60 60 60 1 1 30 90 0.866 0.866 1.732

Circles Circumference is distance around the circle Radius is distance from center to circumference Diameter is longest chord and it goes through center Thales Theorem – angle inside semi-circle is right The circumference is equal to the diameter times π. C = πd = 2πr π = 3.1416 Diameter Thales Radius

Loss of field characteristic

Loss of field characteristic

Loss of field characteristic

Loss of field characteristic

Cartesian Planes Y X

Cartesian Planes Y + - + X -

Cartesian Planes Y X

Cartesian Planes Y 900 1800 00 X 2700 Or -900

Cartesian Planes Y 900 Vc Va 1800 00 Ia X Vb 2700 Or -900

Power Plane Q P Watts flowing out Inductive VARs (unless at a generator)

Power Plane Q Watts flowing out P Inductive VARs VA (unless at a generator) VA

Power Plane Inductive VARs (at a generator) Q VA Watts flowing out P

Impedance Plane X Reactance Resistance R

Impedance Plane X R Reactance Impedance – i.e. line impedance Resistance R

Impedance Plane with Mho Characteristic X R

Getting to the Impedance Plane R = V/I Z = V</I< Z = 100v<0 / 10a < -20 Polar division: divide magnitudes and subtract angles Z = (100/10) < 0 – (-20) Z = 10 < 20 Y 900 Z Va 1800 00 X Ia 2700 Or -900

Getting to the Impedance Plane R = V/I Z = V</I< Z = 100v<0 / 10a < -20 Polar division: divide magnitudes and subtract angles Z = (100/10) < 0 – (-20) Z = 10 < 20

Getting to the Impedance Plane R = V/I Z = V</I< Z = 100v<0 / 10a < -20 Polar division: divide magnitudes and subtract angles Z = 100/10 < 0 – (-20) Z = 10 < 20 X 900 Z Va 1800 00 R Ia 2700 Or -900

Polar Diagram of an Impedance Unit

Ratios Ratios are used to compare two quantities They can be expressed as comparisons - 2:3 or as fractions - 2/3 We see them in transformers – 115kV/12.47kV The full description of transformer parameters is: a (turns ration) = N1 / N2 = V1 / V2 = I2 / I1 Can be simplified by dividing 115/12.47 = 9.2/1 Also CTs 2000/5 = 400/1 And PTs 115,000/115 = 1000/1

Per Unit 11 men who play soccer together can be referred to as a team 11 players 1 team 11 1 per unit

Per Unit This makes discussion of leagues much easier Instead of listing all 11 players every time that group is mentioned, we refer to the team name

Per Unit Per unit means putting the base at one Like percentage without the factor of 100 50% is the same as 0.5 per unit A relay value called tap is a base – 2 x tap = 2 per unit Used in some relay settings – differential minimum op and unrestrained are often per unit settings, also directional power in some generator relays

Per Unit Example 40MVA transformer, 115 kV / 12.47kV Rated current would be 40,000,000va/115,000 v/ √3 = 200.8 a If you apply 100 kV, this would be 0.87 per unit voltage; if you applied 230 kV it would be 2 per unit If you measure 100.4 a, this would be 0.5 per unit If you run it at 110 kV and 50 a, you would see 110 x 50 x √3 = 9.53 MVA or about 0.24 per unit MVA

Decimals In the examples above, there were quantities of several orders of magnitude: amps, kV, MVA You must keep your decimals in order! If you use kV and MVA to avoid writing out 0’s, be sure you know what the current designation will be Same with milli’s and micro’s

Significant Digits My calculator tells me √3 = 1.732050808 It calculates that 120 v / √3 = 69.2820323 My test set will differentiate at millivolt level but not micro- or nanovolts Think about how many decimal places you realistically need – usually 69.3 or 69.28 volts is close enough and round off – 0.0-0.4 goes down,0.5-0.9 goes up

Algebra Basic identities: If A = B and B = C, then A = C Properties: Distributive: a(b+c) = ab+ac Associative: a+(b+c) = (a+b)+c and a(bc) = (ab)c Commutative: a+b = b+a and ab = ba

Order of Operations Please Excuse My Dear Aunt Sally Parentheses – complete operations within any parentheses Exponents – resolve any squares or square roots, etc. Multiplication – complete any multiplication Division – same as above Addition – combine anything Subtraction – subtract anything

Examples A2 + B2 = C2, where A = 3 and B = 4 No parentheses, so exponents: A2 = 9, B2 = 16 No multiplication or division, so addition: 9 + 16 = 25 = C2 No subtraction, so find the square root of 25 to get C = 5 a((5 - 3)2 ) + a(5 + 3) = 24 Parentheses: 5-3=2; 5+3 = 8 a(22) + 8a = 24 Exponents: 22 = 4 4a + 8a = 24 Addition: 12a = 24 a = 2

Factoring 18 = 1x18 = 2x9 = 3x6 1,2,3,6,9, and 18 are the factors of 18 You can use them in equations and expressions to simplify a/18 = b/3; since 3 is a factor of 18 you can multiply both sides by 3 to simplify a/6 = b/1 or a/6 = b We use multiples of 10 as factors a lot

Equations Solving equations: do the same thing to both sides a+2 = 5 subtract 2 from both: a+2-2=5-2, a = 3 3a = 6 divide both sides by 3, 3a/3 = 6/3, a = 2 The same applies to addition and multiplication

Examples V=IR Ohm’s Law A2 + B2 = C2 Pythagorean Theorem I=V/R R = V/I A2 + B2 = C2 Pythagorean Theorem A2 = C2 – B2 B2 = C2 – A2 Cosine = Adjacent / Hypotenuse Trig Adjacent = Cosine x Hypotenuse Hypotenuse = Adjacent / Cosine

Calculator Tips

Example Problems

Double Check Does the answer make sense? If you work backwards from your answer, do you get your original values: if solving for impedance, work back with the impedance and voltage – do you get the original current?

Questions? Resources The Relay Testing Handbook Chris Werstiuk   The Relay Testing Handbook Chris Werstiuk Protective Relaying Quick Reference Power Engineers Several pocket references for power calculations, etc.  Lots of sites on the Internet Prepared by Bill Unbehaun of Tacoma Power for The Hands On Relay School.