19 27 4 1. This is an Arithmagon….

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Presentation transcript:

19 27 4 1. This is an Arithmagon…

19 27 4 2. Look at the 2 “top” squares…

27 is 8 bigger 19 27 4 3. See which one is bigger, and by how much.

19 27 a 4 4. If the bottom-left circle is a…

19 27 a 4 a + 8 5. …then the bottom-right corner is a + 8.

19 27 a 4 a + 8 2a + 8 6. This means 4 equals 2a + 8.

19 27 a -4 a + 8 2a 7. Take away 8… and we find out -4 is 2a.

19 27 a -2 a + 8 a 8. This means a must equal -2.

19 27 -2 4 6 9. Knowing what a equals, we can fill in the 2 bottom circles…

21 19 27 -2 4 6 10. Which just leaves the top circle to fill in… and the Arithmagon is solved!