Balancing Redox Reactions

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Presentation transcript:

Balancing Redox Reactions Problem 4.74 a Balancing Redox Reactions

More Oxidation Numbers Problem 4.74 a) “Electrons lost = Electrons gained” (2) Nitrate -1 8 HNO3 + K2CrO4 + Fe(NO3)2  1 3 +1 +5 -2 +1 +6 -2 +2 +5 -2 Oxidation Fe2+ loses 1 electron to become Fe3+  Need 3 Fe2+ to lose 3 electrons (3) Nitrate -1 (3) Nitrate -1 2 KNO3 + Fe(NO3)3 + Cr(NO3)3 + H2O 3 4 +1 +5 -2 +3 +5 -2 +3 +5 -2 +1 -2 Last Steps...... Balance “K” Reduction Balance “NO3” Cr6+ gains 3 electrons to become Cr3+ Balance “H”