Design procedure for an Integrator

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Design procedure for an Integrator By Bhagyashri Tanaji Thorat Assistant Professor Department of Electronics & Telecommunication Hope Foundation’s International Institute of Information Technology Hope Foundation’s International Institute of Information Technology, I²IT, P-14 Rajiv Gandhi Infotech Park, Hinjawadi, Pune - 411 057 Tel - +91 20 22933441 / 2 / 3 | Website - www.isquareit.edu.in ; Email - info@isquareit.edu.in

Design procedure for an Integrator If gain is not given in problem statement assume gain =10 From the value of gain. Assume R1& calculate RF. Calculate fa from fb 𝑓𝑎=𝑓𝑏/10 Calculate 𝐶 𝐹 from the value of 𝑓 𝑎 Calculate 𝑅 𝐶𝑜𝑚𝑝 = 𝑅 1 ∥ 𝑅 𝐹 Hope Foundation’s International Institute of Information Technology, I²IT, P-14 Rajiv Gandhi Infotech Park, Hinjawadi, Pune - 411 057 Tel - +91 20 22933441 / 2 / 3 | Website - www.isquareit.edu.in ; Email - info@isquareit.edu.in

Problem statement to design Integrator Design a practical Integrator circuit to properly process input sinusodial waveform upto 1kHz . The input amplitude is 10 mV. Hope Foundation’s International Institute of Information Technology, I²IT, P-14 Rajiv Gandhi Infotech Park, Hinjawadi, Pune - 411 057 Tel - +91 20 22933441 / 2 / 3 | Website - www.isquareit.edu.in ; Email - info@isquareit.edu.in

Circuit diagram Integrator Hope Foundation’s International Institute of Information Technology, I²IT, P-14 Rajiv Gandhi Infotech Park, Hinjawadi, Pune - 411 057 Tel - +91 20 22933441 / 2 / 3 | Website - www.isquareit.edu.in ; Email - info@isquareit.edu.in

Solution Given 𝑓=1 𝑘𝐻𝑧 ;𝑉𝑖=10 𝑚𝑉 ∴𝑓𝑏=1 𝑘𝐻𝑧 Assume dc gain 10 𝑓𝑏 ≥10 𝑓𝑎 & 𝑓𝑎≤100 𝐻𝑧 𝑓𝑎= 1 2𝜋 𝑅 𝐹 𝐶 𝐹 𝑅 𝐹 𝐶 𝐹 = 1 2×3.14×100 𝐻𝑧 =1.59× 10 −3 Hope Foundation’s International Institute of Information Technology, I²IT, P-14 Rajiv Gandhi Infotech Park, Hinjawadi, Pune - 411 057 Tel - +91 20 22933441 / 2 / 3 | Website - www.isquareit.edu.in ; Email - info@isquareit.edu.in

solution 𝑅 𝐹 𝑅 1 =10 ∴ 𝑅 1 =10 𝑘𝛺 & 𝑅 𝐹 =100 𝑘𝛺 𝑅 𝐹 𝑅 1 =10 ∴ 𝑅 1 =10 𝑘𝛺 & 𝑅 𝐹 =100 𝑘𝛺 Substituting value of 𝑅 𝐹 𝐶 𝐹 = 1.59 × 10 −3 100 × 10 3 =15.91 𝑛𝐹 Hope Foundation’s International Institute of Information Technology, I²IT, P-14 Rajiv Gandhi Infotech Park, Hinjawadi, Pune - 411 057 Tel - +91 20 22933441 / 2 / 3 | Website - www.isquareit.edu.in ; Email - info@isquareit.edu.in

solution Calculate 𝑅 𝐶𝑜𝑚𝑝 = 𝑅 1 ∥ 𝑅 𝐹 = 10 𝑘𝛺 100 𝑘𝛺 ≈ 10 𝑘𝛺 Hope Foundation’s International Institute of Information Technology, I²IT, P-14 Rajiv Gandhi Infotech Park, Hinjawadi, Pune - 411 057 Tel - +91 20 22933441 / 2 / 3 | Website - www.isquareit.edu.in ; Email - info@isquareit.edu.in

For further details please feel free to contact Bhagyashri Thorat Thank You For further details please feel free to contact Bhagyashri Thorat Department of Electronics & Telecommunication Hope Foundation’s International Institute of Information Technology, I²IT P-14, Rajiv Gandhi Infotech Park, MIDC Phase 1, Hinjawadi, Pune – 411 057 Tel +91 20 22933441 / 2 /3 www.isquareit.edu.in bhagyashrit@isquareit.edu.in | info@isquareit.edu.in