Chem HW 7-2.

Slides:



Advertisements
Similar presentations
Review Unit 6 Double Edged Sword.
Advertisements

1 Ca 2+ + CO 3 2- CaCO 3 NH 3 + H + NH 4 + Zn + 2HCl ZnCl 2 + H 2 Ca + F 2 CaF 2 Precipitation Acid-Base Redox (H 2 Displacement) Redox (Combination) Classify.
Molarity and Dilutions
Making Dilutions from Solutions
Examples-Molarity and Dilutions. Example What is the molarity of a solution that contains 4.5 moles of sucrose in L of water?
Spring Semester, 2013 Mrs. L. Fox. Concentration The amount of a dissolved substance occupying a given volume of the solution.
Dilutions. Solve problems involving the dilution of solutions. Include: dilution of stock solutions, mixing common solutions with different volumes and.
Thursday, March 6, 2008 Discussion of Molarity Lab Results Introduce Section 15.2b -- Dilutions Homework: Pg. 555, #31a-d, 32, 33, 34.
Chapter 16 – Solutions Mr.Yeung. Lesson 5 - Objectives Take up questions Dilutions (Super important)!
Solution Concentration. Review  A solution is a homogeneous mixture.  The solvent is the major component of the solution.  The solute is the minor.
Unit 10B Review Reg Chem When a solution sits out over a long period of time and water evaporates the concentration of the solution __________.
Solution Concentration Section 14.2 Concentration - amount of solute dissolved in a specific amount of solvent concentrated - a lot of solute dilute.
Preparing a Molar Solution
Molarity = Molarity ( M ) moles solute liters of solution
Notes 15.2 Describing Solution Composition. Mass Percent Mass percent= mass of solute X 100 mass of solution = grams of solute X 100 grams of solute +
Section 15.2 Describing Solution Composition 1. To understand mass percent and how to calculate it Objective.
III. Molarity Topic 9 The Mole. A. Molarity Concentration of a solution. total combined volume substance being dissolved.
MOLARITY A measurement of the concentration of a solution. Molarity (M) is equal to the moles of solute (n) per liter of solution M =__n__ = mol volL.
CONCENTRATION OF SOLUTIONS. Solute + The amount of solution can be expressed by: - mass m (g, kg) or - volume V (cm 3, mL, dm 3, L, m 3 ) m = V x  -
Molarity  Unit of Concentration  There are many units of concentration  Molarity is most useful to the chemist M = moles of solute Liters of solution.
Daily Inquiry: 1.Many solutions are described as concentrated or dilute. Distinguish between these two terms. 2.A solution is made by dissolving 4.75 g.
Solutions Chapter 14.
Solutions, Problems, Solutions, Problems. Does it ever end?
Daily Inquiry: 1.Many solutions are described as concentrated or dilute. Distinguish between these two terms. 2.A solution is made by dissolving 4.75 g.
Molarity • Molarity is a measure of molar concentration
Dilutions.
Molarity & Dilutions. Molarity Concentration – Measure of the amount of solute that is dissolved in a given quantity of solvent Dilute solution – Contains.
Dilution Adding water to a solution. Dilution The number of moles of solute doesn’t change if you add more solvent! The # moles before = the # moles after.
Two methods for Preparation of a desired volume of a Molar Solution  1) Preparation from a solid solute.  2) Preparation by Dilution of a Concentrated.
Concentrations of Solutions
Solution Concentration
HW 7-3 P. 480, #124: When 50. mL of 5.4 M NaCl is diluted to a final volume of 300. mL, what is the concentration of the diluted solution? Mc =
Making Molar Solutions
Making a solution.
Molarity, Dilution, and pH
8.6 Making Molar Solutions
Solutions & Chemical Equilibrium
Unit 13: Solutions & Equilibrium
Aim # 18: What are some other methods of expressing the concentration of a solution? H.W. # 18 Study pp (sec ) STUDY class notes Complete.
Unit V: The Mole Concept
Making Dilutions M1 x V1 = M2 x V2
Daily Science April 30 Determine if the following are soluble or insoluble NaCl HgS LiOH Will there be a precipitate in the following reaction? NaCl +
DILUTING A STOCK SOLN To make a soln less concentrated: add solvent
Concentration of Solutions
Unit V: The Mole Concept
Warm up - Solutions.
Unit: Acids, Bases, and Solutions
Unit 13: Solutions & Equilibrium
CONCENTRATION OF SOLUTIONS
Solutions: Concentrations
Section 2: Concentration
Molarity (m).
Molarity & Dilution.
Colligative Properties
Solutions solute dissolved in a solvent
12-3: Concentration of Solutions
Solutions Chapter 12.
A homogeneous mixture in which the components are uniformly mixed
Molar Concentrations.
Chapter 4: Concentrations and Titrations
Solution Concentration
Two methods for Preparation of a desired volume of a Molar Solution
Unit 3, Lesson 14: Dilutions
Which one of these is more concentrated?
Unit 12. Solutions (including Molarity)
II. Molarity.
Unit 2 Lesson 3 Molarity Video Disk Unit 6 Demo Magic Sand
Concentrations of Solutions
Concentration of Solution
Concentration = # of moles volume (L) V = 1000 mL V = 1000 mL
Presentation transcript:

Chem HW 7-2

250. mL of 0.300 M KMnO4 from solid KMnO4. ( ) 0.300 moles KMnO4 .250 L = 0.0750 mol KMnO4 1.00 L 39.098g + 54.938g + 4(15.999) = 158.032 ( ) 158.032 g KMnO4 0.0750 mol KMnO4 = 11.9 g KMnO4 1 mol KMnO4

KMnO4 Detailed Directions: Dissolve _____ g of _______ in enough water to prepare _______ mL of solution. Diagram steps below: 11.9 250 ml 11.9 g KMnO4 Dissolve Add water to 250 ml

) ) ( ( = 0.125 mol KI = 20.8 g KI 500. mL of 0.250 M KI from solid KI 0.250 moles KI 0.500 L = 0.125 mol KI 1.00 L 39.10g + 126.90g = 166.00g ( ) 166.00 g KI 0.125 mol KI = 20.8 g KI 1 mol KI

KI Detailed Directions: Dissolve _____ g of _______ in enough water to prepare _______ mL of solution. Diagram steps below: 20.8 500 ml 20.8 g Dissolve Add water to 500 ml

2.00 L of 4.00 M C6H12O6 from solid C6H12O6 ) ( 4.00 mole C6H12O6 = 8.00 mol C6H12O6 2.00 L solution 1 L solution 6(12.01 g) + 12(1.01 g) + 6(16.00 g) = 180.18 g ( ) 180.18 g C6H12O6 8.00 mol C6H12O6 = 1440g C6H12O6 1 mol C6H12O6

C6H12O6 Detailed Directions: Dissolve _____ g of _______ in enough water to prepare _______ of solution. Diagram steps below: 1440 2.00 L 1440g C6H12O6 Dissolve Add water to 2.00 L

4. 500. mL of 6.00 M from 12.4 M (concentrated) HCl stock solution. Solve for.. Mc = 12.4 M Vc = ? Md = 6.00 M Vd = 500. mL McVc = MdVd Vc = Md * Vd Mc Vc = 6.00 mol/L * 500. mL 12.4 mol/L = 242 ml

12.4 Recipe: Dilute ____ mL of the _____ M stock solution with enough water to prepare _______ mL of solution. Diagram steps below: 242 500 242 ml of 12.4 M stock mix

5. 100. mL of 1.00 M H2SO4 from 18.0 M (concentrated) H2SO4. Solve for.. Mc = 18.0 M Vc = ? Md = 1.00 M Vd = 0.100 L McVc = MdVd Vc = Md * Vd Mc Vc = 1.00 mol/L * 0.100L 18.0 mol/L = 0.00556 L = 5.56 ml

18.0 Recipe: Dilute ____ mL of the _____ M stock solution with enough water to prepare _______ mL of solution. Diagram steps below: 5.56 100 5.56 ml of 18.0 M stock mix

McVc = MdVd Vc = Vc = 6. 25.0 mL of 3.00 M HNO3 from 15.0 M HNO3 Solve for.. Mc = 15.0 M Vc = ? Md = 3.00 M Vd = 0.025 L McVc = MdVd Vc = Md * Vd Mc Vc = 3 mol/L * 0.025L 15.0 mol/L = 0.00500 L = 5.00 ml

15.0 Recipe: Dilute ____ mL of the _____ M stock solution with enough water to prepare _______ mL of solution. Diagram steps below: 5.00 25.0 5.00 ml of 15.0 M stock mix