Final Review Double Jeopardy

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Presentation transcript:

Final Review Double Jeopardy Chapter 1 200 Chapter 2 200 Chapter 3 200 Chapter 4 200 Chapter 5 200 Chapter 3 400 Chapter 1 400 Chapter 2 400 Chapter 4 400 Chapter 5 400 Chapter 1 600 Chapter 4 600 Chapter 5 600 Chapter 2 600 Chapter 3 600 Chapter 1 800 Chapter 2 800 Chapter 3 800 Chapter 4 800 Chapter 5 800 Chapter 1 1000 Chapter 2 1000 Chapter 3 1000 Chapter 4 1000 Chapter 5 1000

Chapter 1 200 Simplify [6 • (3 + 5)] + 2 50

Chapter 1 400 Evaluate 6p - 3q when p = -2 and q = 3 -21

Chapter 1 600 A basketball court is 30 yards long and 15 yards wide. How many square yards? 450

Chapter 1 800 Evaluate the Expression (x + y)2 for x = 4 & y = 7 121

Chapter 1 1000 Evaluate the Expression 13 + (4 • 3)2 - 6. 151

Chapter 2 200 Express the phrase“The Product of a number and 6 is 42” as an equation. 6x = 42

Chapter 2 400 Evaluate |y| + |x| when y = -2 and x = -3 5

Chapter 2 600 Evaluate -14 - 6 + (-10) -30

Chapter 2 800 Simplify: -(-3) - (-7) + 9 19

Chapter 2 1000 -3 -6 -4 -7 7 -4 -3 3 - 1 1 10 -7

Chapter 3 200 Simplify: 3(-2 - x) -3(5 - x) -21

Chapter 3 400 Evaluate 3ab when a=7 & b=5 4a - 3 21 5

Chapter 3 600 Add 5 to both sides State the 1st step for solving the equation: x - 5 = 29 Add 5 to both sides

Chapter 3 800 Solve ½x = 12 X = 24

Chapter 3 1000 Solve 7x - 3 = 60 X = 9

Chapter 4 200 Graph y = 2/3x - 3

Chapter 4 400 Graph 3x + 2y = 12 using the x and y intercepts.

Click here for the Daily Double Chapter 4 600 Click here for the Daily Double

Chapter 4 ??? Graph y = -2

Chapter 4 800 Graph 2x - 6 = y

Chapter 4 1000 Graph 3x + 2y = 6

Solve the absolute value equation |x + 5| = 8 Chapter 5 200 Solve the absolute value equation |x + 5| = 8 X = 3 & x = -13

Chapter 5 400 The points (1,5) & (5,-3) Find the Slope m = -8/4 = -2

Chapter 5 600 y = -3x + 3 (x1,y1) = (0,3) & (x2,y2) = (2,-3) What is the slope-intercept form of the equation if (x1,y1) = (0,3) & (x2,y2) = (2,-3) y = -3x + 3

Chapter 5 800 What is the slope-intercept form of the equation if (x1,y1) = (4,0) & (x2,y2) = (0,-5) y = 5/4x + 5

Chapter 5 1000 Graph the absolute value equation y = 3|x + 2| - 3

Chapter 4 400 Y X