Three masses are connected by light strings as shown in the figure  Three masses are connected by light strings as shown in the figure. M1 = 4 kg, M2 = 2 kg, and M3 = 3 kg, The pulley is light and frictionless. Find the tension in the string connecting M2 and M3. A. 2.3 N B. 5.7 N C. 26.1 N D. 0.2 N E.. 16.0 N 842-1

A 90 kg man stands on a scale in an elevator A 90 kg man stands on a scale in an elevator. What is the acceleration (magnitude and direction) of the elevator when the scale reads 110 kg? A. 9.8 m/s**2 upward B. 1.8 m/s**2 downward C. 4.3 m/s**2 upward D. 2.2 m/s**2 upward E. 8.0 m/s**2 downward 842-1

A 90 kg man stands on a scale in an elevator A 90 kg man stands on a scale in an elevator. What is the acceleration (magnitude and direction) of the elevator when the scale reads 110 kg? A. 9.8 m/s**2 upward B. 1.8 m/s**2 downward C. 4.3 m/s**2 upward D. 2.2 m/s**2 upward E. 8.0 m/s**2 downward 842-1

What do we want to do today?! Tuesday: 22-1-1440 A bit of housekeeping Conclude chapter-6 Prof. Zain Yamani Office: 15-3100/ 3102; Phone: 860-4363; Mobile: 0504608515 E-Mail: zhyamani@kfupm.edu.sa; HP: http://faculty.kfupm.edu.sa/phys/zhyamani

Help session tonight Building-6, Room-125 A bit of housekeeping Help session tonight Building-6, Room-125

A bit of housekeeping Attendance If you come late, please make me aware during the (end of) the same lecture.

A bit of housekeeping Two types of truths! 

What does “inertial reference frame” mean? Is earth (i.e. the ground) an inertial frame or rather an non-inertial frame of reference?

Chapter-6: Applications of Newton’s Laws Friction Drag force Uniform Circular Motion

Friction Static vs Kinetic Figure out the normal force Example: block on an incline

The Figure shows an initially stationary block of 1 The Figure shows an initially stationary block of 1.00 kg mass on a rough floor. A force F, of magnitude 4.90 N and making an angle  = 20.0° with the horizontal, is then applied to the block. What is the magnitude of the acceleration of the block across the floor if the coefficient of kinetic friction k = 0.300? A) 2.17 m/s2 B) 3.62 m/s2 C) 5.73 m/s2 D) 1.55 m/s2 E) 1.01 m/s2 141-F

The Figure shows an initially stationary block of 1 The Figure shows an initially stationary block of 1.00 kg mass on a rough floor. A force F, of magnitude 4.90 N and making an angle  = 20.0° with the horizontal, is then applied to the block. What is the magnitude of the acceleration of the block across the floor if the coefficient of kinetic friction k = 0.300? A) 2.17 m/s2 B) 3.62 m/s2 C) 5.73 m/s2 D) 1.55 m/s2 E) 1.01 m/s2 141-F

A 3 kg block on a 30 deg incline is connected by a light string over a frictionless massless pulley to a 4 kg mass (see figure). The coefficient of kinetic friction between the block and the plane is 0.2. Find the acceleration of the blocks. 3.78 m/s**2 5.34 m/s**2 8.43 m/s**2 7.58 m/s**2 2.77 m/s**2 842-1

A 3 kg block on a 30 deg incline is connected by a light string over a frictionless massless pulley to a 4 kg mass (see figure). The coefficient of kinetic friction between the block and the plane is 0.2. Find the acceleration of the blocks. 3.78 m/s**2 5.34 m/s**2 8.43 m/s**2 7.58 m/s**2 2.77 m/s**2 842-1

Uniform Circular Motion The centripetal force Car speeding on a flat/ horizontal track Car speeding on an inclined track Loop the loop Loss of sense of direction during military air maneuvers

A car moves on a curved, unbanked highway as shown in the figure A car moves on a curved, unbanked highway as shown in the figure. The radius of curvature of the highway is 100 m. What is the maximum speed of the car if it is not to skid ? (coefficient of static friction between the tires and the road = 0.50) 69.3 m/s 9.11 m/s 41.0 m/s 22.1 m/s 4.01 m/s 842-1

A car moves on a curved, unbanked highway as shown in the figure A car moves on a curved, unbanked highway as shown in the figure. The radius of curvature of the highway is 100 m. What is the maximum speed of the car if it is not to skid ? (coefficient of static friction between the tires and the road = 0.50) 69.3 m/s 9.11 m/s 41.0 m/s 22.1 m/s 4.01 m/s 842-1

Find the tension in the string. A 0.5 kg stone is tied to the end of a string of length 0.25 m and is rotated in a horizontal plane at a constant rate of 1.5 rev/s. The string makes an angle beta with the vertical (see figure). Find the tension in the string. 4.04 N 48.2 N 11.1 N 29.9 N 7.11 N 842-1

Find the tension in the string. A 0.5 kg stone is tied to the end of a string of length 0.25 m and is rotated in a horizontal plane at a constant rate of 1.5 rev/s. The string makes an angle beta with the vertical (see figure). Find the tension in the string. 4.04 N 48.2 N 11.1 N 29.9 N 7.11 N 842-1

Chapter-6 slides 

Have you ever used Mathematica?