MATH 1310 Section 2.8.

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Presentation transcript:

MATH 1310 Section 2.8

Absolute Value Equations

Solve the following:

e. |2x – 1| = |x + 7|

Popper 06: 4 + |x + 8| = 12 a. {-8, 8} b. {0, 16} c. {-16, 0} d. No Answer |2x + 4|= 3 a. {-0.5} b. {-3.5} c. {-3.5, -0.5} d. No Answer

Popper 06…continued |3x – 2| + 1 = 4 a. {-1/3, 5/3} b. {1/3, 5/3} c. {5/3} d. No Answer 4. |x + 3| = -4 a. {-7, 7} b. {-7} c. {-7, -1} d. No Answer

Popper 07 1. |2x + 6| ≥ 8 [-7, 1] b. [-7, 7] c. (-∞, -1] U [7, ∞) d. (-∞, -7] U [1, ∞) 2. -4|x – 3| + 5 > -7 (-∞, 0) U (6, ∞) b. (0, 6) c. (-6, 6) d. No Solution 3. |5x + 5| + 3 < 28 a. (-30, 20) b. (-6, 4) c. (-∞, 4) U (6, ∞) d. (-∞, -30) U (20, ∞)

Popper 07…continued 4. 5|x – 12| + 8 ≤ 8 {12} b. {0} c. (-∞, ∞) d. No Solution 5. |2x + 7| + 9 ≥ 4 a. (-∞, -6] U [-1, ∞) b. [-6, -1] c. (-∞, ∞) d. No Solution