E photon = h , h = Planck’s constant = 6.63x10-34 J s  = Frequency

Slides:



Advertisements
Similar presentations
How can we tell if two quantities are directly proportional?
Advertisements

Celsius-to-Fahrenheit: F = 1.8C + 32
At what temperature are the Celsius and Fahrenheit readings equal?
D = (48.0 g) / (6.0 mL) = 8 g/mL  8.0 g/mL
QUESTION: A 25.0 gram sample of a compound is found to be 24% chlorine by mass. What is the percentage of chlorine in a 50.0 g sample of the compound?
Bohr assumed electrons move around the nucleus in circular orbits.
QUESTION: How many ways can the magnetism generated by the orbital motion of an electron in a 3p orbital be oriented? A. 1, B. 3, C. 5, D. 7 Magnetism.
Mass of proton : x kg, or u QUESTION: Which of the following has the largest total mass? A. 2 protons + 4 electrons B. 2 neutrons.
QUESTION: Which of the following elements is a transition metal? A. silicon, B. lead, C. sodium, D. chromium SCRIPT: Which of the following elements.
SO3: one Sulfur atom: 16 protons
Uncertainty of g: tenths place
A. 2.40x103 km min-1, B. 6.67x10-1 km min-1 C km min-1
Which of these is the formula of a reactant in this reaction?
QUESTION: Which of the following describes a cation? A. an aluminum ion (Al3+), B. an oxygen atom that has gained 2 electrons C. an ion with 17 protons.
General strategy for converting units:
infrared, microwave, radiowave
Ions are formed by loss or gain of electrons.
How many cations are in 2.00 mol Na3PO4?
How many atoms of carbon are in a 2.50 mol sample of carbon?
To convert Celsius reading to Fahrenheit: F = 1.8C + 32
650 nm = red, 580 nm = yellow, 450 nm = blue
Individual count  / Avogadro’s number  Mole count n = N / NA
E photon = eV / 22 – (-13.6 eV / 12) = 10.2 eV, or 1.63x10-18 J
Here’s a general strategy for determining empirical formulas.
A measurement of 2.50 mm is equivalent to ...
QUESTION: Which of the following describes an anion? A. a sodium ion (Na+), B. a calcium ion that has lost 2 electrons C. an ion with 8 protons and 10.
500 nm corresponds to green light.
QUESTION: Which of the following is a metalloid? A. Potassium, B. Silicon, C. Iron, D. Helium SCRIPT: Which of the following is a metalloid? A.
In nature, substances are typically mixed.
Mass of proton or neutron: 1.0 u Mass of electron: u
Ions are formed by loss or gain of electrons.
A. 0.8 g/mL, B g/mL, C g/mL, D. 1.3 g/mL
One Ca2+ ion: +2 One CO32- ion: -2
There are 3 orbitals in a p subshell (ml = -1, 0, or +1).
IF Period: T = 0.5 s [one-half second per cycle]
Ions are formed by loss or gain of electrons.
QUESTION: The volume of a sphere of radius r is given by the formula: V = (4/3) ()(r3) The radius of a sphere is measured to be 5.00 cm. What is.
Therefore: volume = mass / Density = (5.0 g) / (1.06 g/mL)
A. 1.29x10-3 mg/mL, B mg/mL, C. 1.29x10-6 mg/mL
Here’s a general strategy for determining empirical formulas.
Mathematically, this implies that the ratio of the amount of element
QUESTION: Consider the reaction: N2 + 3 H2  2 NH3 Suppose a reaction mixture initially contained mol N2, and now contains only mol N2 as.
Estimated uncertainty: + (½) (Range)
How many neutrons does an O-18 atom have? A. 8, B. 10, C. 16, D. 18
One Na+ ion: +1 One CO32- ion: -2
QUESTION: How should the result of the following calculation be reported, assuming that 1.8 and 32 are exact numbers? 32 + (1.8)(2.37) A. 36,
Total energy = Kinetic + Potential
What is the Kelvin temperature equivalent to 50.00oF?
The oxygen-to-carbon ratio in that sample is x over 36.0 HIGHLIGHT
What is the Kelvin temperature equivalent to 25.00oC?
QUESTION: Illustrated below is a snapshot of the electric field component of an electromagnetic wave as it travels through space. At which of the locations.
Each calcium ion has a charge of +2,
E3 = -(13.6/32) eV = eV E2 = -(13.6/22) eV = eV
Allowed values of principal quantum number (n): positive integers
QUESTION: Consider the reaction: N2 + 3 H2  2 NH3 How much NH3 is produced if mol H2 is consumed? A mol, B mol, C mol Consider.
=c/; Lower frequency
The area of a circle is found to be 2.4 cm2. What is the area in m2?
QUESTION: Consider the reaction: N2 + 3 H2  2 NH3 Suppose mol of N2 is used up in this reaction. How much NH3 is produced? A g, B
Ions are formed by loss or gain of electrons.
QUESTION: How should the result of the following calculation be reported? (0.0050)(39.0) A. 0.20, B. 0.21, C , D
CLICK PAUSE END RECORDING
QUESTION: What is the maximum number of of electrons that can be assigned to a 2p orbital of an atom? A. 2, B. 3, C. 6, D. 10 Pauli’s Exclusion.
A. an element and two compounds, B. two elements and a compound,
Here’s a general strategy for determining empirical formulas.
X-78: mass=78.0 u, abundance = 30.0%
0.800 m has three significant digits
What do molecules and polyatomic ions have in common?
How many moles of CH4 are in 4.00 g of CH4?
What is the mass of 2.00 mol NH3? A g, B g, C g
80.00 g has four significant digits
Presentation transcript:

E photon = h , h = Planck’s constant = 6.63x10-34 J s  = Frequency QUESTION: What is the energy of a photon of ultraviolet radiation with a wavelength 250 nm? A. 5.0 eV, B. 2.5 eV, C. 4.0x10-2 eV 1 eV = 1 electron volt = energy gained by an electron that is accelerated through a potential difference of one volt = (charge of electron) (potential difference) = (1.60x10-19 C) ( 1 V) = 1.60x10-19 CV 1 CV = 1 J C=Coulomb; V=Volt; J=Joule E photon = h , h = Planck’s constant = 6.63x10-34 J s  = Frequency = c/ = (3.00x108 m/s) / (250x10-9 m) = 1.20x1015 s-1 E photon = (6.63x10-34 J s) (1.20x1015 s-1) = 7.96x10-19 J Conversion factor: 1 eV = 1.60x10-19 J E photon = 7.96x10-19 J x (1 eV / 1.60x10-19 J) = 4.98 eV  5.0 eV SCRIPT: What is the energy of a photon of ultraviolet radiation with a wavelength 250 nm? A. 5.0 eV, B. 2.5 eV, C. 4.0x10-2 eV CLICK The energy of a photon is directly proportional to the frequency. Specifically, it is equal to Planck’s constant, h HIGHLIGHT h times the frequency nu HIGHLIGHT nu The value of Planck’s constant is 6.63x10^-34 joule second… HIGHLIGHT We’re not given the frequency in the question, but we are given the wavelength, which we can use to calculate the frequency. The frequency of an electromagnetic wave is equal to the speed of the wave, c.. Divided by the wavelength, lambda… The speed of electromagnetic waves is 3.00 x 10^8 meters per second. HIGHLIGHT And we’re given a wavelength of 250 nanometers --- highlight 250 nm. For unit consistency, the wavelength value we plug in to our formula must be in meters. So, we change 250 nanometers to 250 x 10^-9 m, since a nanometer is equal to 10^-9 meter CALLOUT “1 nm = 10-9 m” pointing to “10-9 m” When we do the calculation … Meters cancel out CLICK CLICK Punching these numbers into a calculator, we find that the frequency is 1.20x10^15 cycles per second. We can now calculate the energy of the photon….which is equal to Planck’s constant, 6.63x10^-34 joule second Times the frequency, which we just calculated to be 1.20x10^15 per second Second and per per second cancel out. And we get an answer of 7.96x10^-19 joules. Photon energies tend to be small numbers like this… we it is more convenient to express it in a smaller unit. The most commonly used unit is electron volts. One electron volt is equivalent to 1.60x10^-19 joules. AN electron volt is the energy gained by an electron when it is accelerated through a potential difference of 1 volt. This energy is equal to the charge of the electron, 1.60x10^-19 Coulombs, times the potential difference of 1 volt, Or 1.60x10^-19 Coulomb volt. One Coulomb volt is equal to one joule. CLICK To convert our answer to electron volts, we multiply it HIGHLIGHT by one electron volt HIGHLIGHT divided by 1.6x10^-19 joules This gives us an answer of 4.98 electron volts, which we round off to 5.0 electron volts. There are two significant digits in 250 nm. So only keep two significant digits in our final answer. Note that we kept an extra digit in the intermediate results. This is so that we do not build up round off errors. The correct answer is A. PAUSE CLICK END RECORDING.

Video ID: 2-1-5 © 2008, Project VALUE (Video Assessment Library for Undergraduate Education), Department of Physical Sciences Nicholls State University Author: Glenn V. Lo Narrator: Funded by Louisiana Board of Regents Contract No. LA-DL-SELECT-13-07/08