MATH 1310 Section 3.6.

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Presentation transcript:

MATH 1310 Section 3.6

Combining Functions:

Popper 15: Question 1: Function Answer: 3x4 + 2x3 – x2 – 8 b. -3x4 – 2x3 – x2 + 8 c. -3x4 – 3x3 + 8 d. -3x4 – 2x3 + x2 + 8 Question 2: Domain: a. (-∞, ∞) b. (0, ∞) c. [0, ∞) d. (-∞, 8] Question 3: Function Answer: 3x2 – (8/x2) b. 3x2 + 2x – (8/x2) c. -3x2 – 2x + (8/x2) d. 3x2 + (8/x2) Question 4: Domain: a. (-∞, ∞) b. [0, ∞) c. (-∞, 0) d. (-∞, 0) U (0, ∞)

Popper 15…continued: Question 5: a. -16 b. 39 c. 10 d. No Solution

Composition of Functions

Popper 15 continued: Consider the functions: 𝑓 𝑥 = 𝑥 2 +2𝑥−8 𝑎𝑛𝑑 𝑔 𝑥 = 𝑥+3 . 7. Determine 𝑓 °𝑔 𝑥 a. 𝑥+3 −8 b. 𝑥 2 +8𝑥+7 c. 𝑥+2 𝑥+3 −5 d. 𝑥 2 +2𝑥−5 8. Determine 𝑓 °𝑔 6 a. 2.36 b. 7 c. 43 d. 3 9. Determine: 𝑓 °𝑔 −3 a. -8 b. 10 c. -5 d. No Answer 10. Determine 𝑓 °𝑔 −5 a. -2 b. 10 c. 0 d. No Answer

Given the following table of values, determine: (f o g)(4). x f(x) g(x) 4 2 -1 6 3 8