Estimation Method of Moments Industrial Engineering

Method of Moments Recall from Data Analysis, we had three measures for failure time data s2 = 302.76 X 1 . 19 =

Method of Moments For Failure Time data, we now have three measures for the data Exponential ?? s2 = 302.76 X 1 . 19 =

Method of Moments Recall that for the exponential distribution m = 1/l s2 = 1/l2 If E[ X ] = m and E [s2 ] = s2, then 1/l = 19.1 X 1 . 19 = s2 = 302.76 l 0524 . ˆ =

Method of Moments Recall that for the exponential distribution m = 1/l s2 = 1/l2 If E[ X ] = m and E [s2 ] = s2, then 1/l = 19.1 or 1/l2 = 302.76 X 1 . 19 = s2 = 302.76 l 0524 . ˆ = l 0575 . ˆ =