Area of a a parallelogram In a parallelogram, the height is a segment perpendicular to both bases

If a diagonal is drawn in a parallelogram, 2 identical triangles are formed.

The area of a parallelogram is twice the area of one of the triangles, so an expression to find the area of a parallelogram could be written A = 2 (1/2 bh) which simplifies to A = bh

Area of a parallelogram A = bh Where b is the length of the base and h is the perpendicular height

Since rectangles, rhombuses, and squares are all parallelograms, the area of these shapes can also be found using the same formula A = bh

Find the area of each of the following: Square rectangle 3 yd. 12 in. 22 in. 3 yd. parallelogram 15 ft 9 ft. 8 ft.

Trapezoid A trapezoid is a quadrilateral with exactly 1 pair of parallel sides The height of the trapezoid is the a segment that is perpendicular to both parallel sides of the trapezoid- these parallel sides are the bases- b1 and b2 b1 h b2

A = 1/2 (b1 + b2 ) h Area of a trapezoid Where b1 and b2 are the bases and h is the perpendicular height

Finding areas of trapezoids

A rhombus's diagonals are perpendicular and bisect each other

Area of a rhombus Since a rhombus is a parallelogram, you can use the formula for parallelogram A = bh Or You can use the diagonals formula A = 1/2 d1 d2 Where d1 and d2 represent the diagonals of the rhombus

Find the area of the rhombus Use the parallelogram formula or the diagonal formula 30 in 6 ft 11 in. 5 ft