Conservation of Momentum in Collisions 2

Slides:

Advertisements

Similar presentations

Chapter 9B - Conservation of Momentum

Advertisements

Chapter 5 Momentum Ewen et al. 2005) Objective: Apply the law of conservation of momentum to both elastic and inelastic collisions of two objects. Apply.

Impulse, Momentum and Collisions

Conservation of Momentum

Warm up. Physics Honors AB –Day 1/12/15-1/13/15 Momentum and Impulse.

Momentum and Energy in Collisions. A 2kg car moving at 10m/s strikes a 2kg car at rest. They stick together and move to the right at ___________m/s.

The Law of the Conservation of Momentum Conservation of Momentum The law of conservation of momentum states when a system of interacting objects is not.

Momentum is Conserved in an isolated system.

Principles of Physics. - property of an object related to its mass and velocity. - “mass in motion” or “inertia in motion” p = momentum (vector) p = mvm.

Science Starter A 2 kg object moving east at 12 m/s collides with a stationary 6 kg object. After the collision, the 2 kg object bounces west at 6 m/s.

Momentum and Impulse Review 1.The velocity of a moving mass is called? ans: momentum 2.Force applied in a period of time is called? ans: impulse 3. The.

Collisions basically include every interaction § 8.3–8.4.

1 PPMF102– Lecture 3 Linear Momentum. 2 Linear momentum (p) Linear momentum = mass x velocity Linear momentum = mass x velocity p = mv p = mv SI unit:

Chapter 6 Momentum and Impulse

Chapter 9 - Collisions Momentum and force Conservation of momentum

Momentum. Collisions Perfectly inelastic collisions –When two objects stick together and move as one mass Elastic collisions –When two objects return.

Elastic and Inelastic Collisions. Elastic Collision If 2 colliding objects are very hard and no heat is produced in the collision, KE is conserved as.

The force on an object may not be constant, but may vary over time. The force can be averaged over the time of application to find the impulse.

Lecture 14: Collisions & Momentum. Questions of Yesterday A 50-kg object is traveling with a speed of 100 m/s and a 100-kg object is traveling at a speed.

Physics Section 6.3 Apply the physics of collisions Inelastic collision – two objects stick together after colliding. The two objects become one object.

Momentum and Collisions. Conservation of Momentum.

Law of Conservation of Momentum. The Law of Conservation for Momentum Momentum is always conserved in a collision. It is never created or destroyed! (Just.

1. What is the difference in elastic and inelastic collisions?

Collisions SPH4U. Momentum vs. Energy All interactions conserve momentum. They do not necessarily conserve kinetic energy.

Elastic and Inelastic Collisions

1. What is the difference in elastic and inelastic collisions?

Guidelines for Solving Conservation of Momentum Problems

Do Now: A 1500 kg car speeds up from 15 m/s to 30 m/s in 6 seconds.

Aim: How is momentum and energy conserved together?

Conservation of Momentum

Conservation of Momentum

3.1.2 Conservation of Momentum

Collisions in 1D Lesson 3.

Name 3 vectors and 3 scalars.

Collisions Elastic vs. Inelastic.

A 61 kg lumberjack stands on a 320 kg log that floats on a pond

Conservation of Momentum Problems Answers

The Ballistic Pendulum

Writing Prompt: 10/26/2006 Predict what will happen if a 250 lb. safety runs into a 140 lb. punt returner who was standing still to catch a punt during.

Lesson 6.3 Elastic and Inelastic Collisions

7. Momentum and impulse Momentum:

Conservation of Momentum

p = mv v p m B. Momentum Momentum quantity of motion

Handout, Test Correction, Copy down table

Aim: How do we Analyze elastic collisions?

Conservation of Momentum and collisions

Collisions In collisions momentum is conserved because all of the forces acting are internal forces. Remember: According to the Law of Conservation of.

Aim: How do we use conservation of momentum to analyze collisions?

Collisions and Conservation of Momentum

I. Newton’s Laws of Motion

I. Newton’s 3rd Law For every ACTION force there is an equal an opposite REACTION force. Ex: Hammer hits a nail Action: Hammer hitting nail Reaction: Nail.

Center of Mass & Linear Momentum

Now consider two tennis balls……

The Law of Conservation of Momentum

2.3 Momentum Momentum:

Momentum Objectives (Mom. and Energy Unit)

SCI 340 L22 Collisions basically include every interaction

Collisions Momentum is always conserved in collisions

Momentum Mass X Velocity.

Ch. 6 Momentum and Impulse

The Law of Conservation of Momentum

p = mv v p m B. Momentum Momentum quantity of motion

Impulse-Momentum Principle

Warm-up Checking HW (Conservation of Momentum Practice)

Aim: How do we use conservation of momentum to analyze collisions?

Collisions Chapter 7.5.

Conservation of Momentum Problems Answers

Presentation transcript:

Conservation of Momentum in Collisions 2

Elastic or Inelastic? In an inelastic collision, energy is lost and the deformation may be permanent. An elastic collision loses no energy. The deform-ation on collision is fully restored.

Completely Inelastic Collisions Collisions where two objects stick together and have a common velocity after impact. Before After

mAvAa + mBvBa = mAvAb + mBvBb Example 1: A 60-kg football player stands on a frictionless lake of ice. He catches a 2-kg football and then moves at 40 cm/s. What was the initial velocity of the football? A Given: mA= 2 kg; vABa= 0.4 m/s; mB= 60 kg; vBb= 0m/s B mAvAa + mBvBa = mAvAb + mBvBb Momentum: (mA + mB)vABa = mAvAb Inelastic collision: (2 kg + 60 kg)(0.4 m/s) = (2 kg)vAb vAb= 12.4 m/s

pbefore= p after pbefore= mAvAb +mB vBb pafter= mAvAa +mB vBa Example 2: A 1-kg ball moving to the right at 1 m/s strikes a 2-kg ball moving left at 3 m/s. The 1-kg moves back to the left with a speed of 3 m/s after the collision. If the two balls do not stick together, what is the velocity of the 2-kg ball after the collision? pbefore= p after + A B 3 m/s 1 m/s vBa 1 kg 2 kg pbefore= mAvAb +mB vBb pbefore= (1kg)(+1m/s) +(2kg) (-3m/s) pafter= mAvAa +mB vBa pafter= (1kg)(-3m/s) +(2kg) vBa -5=-3+2vBa vBa = - 1 m/s B moves to the left after collision

Example 3. An 87-kg skater B collides with a 22-kg skater A initially at rest on ice. They move together after the collision at 2.4 m/s. Find the velocity of the skater B before the collision. A B vBa = ? vAb = 0 Common speed after colliding: 2.4 m/s. 22 kg 87 kg vBa= vAa= 2.4 m/s mAvAb + mBvBb=(mA+mB)vABa (87 kg)vBb = (87 kg + 22 kg)(2.4 m/s) (87 kg) vBb=262 kg m/s vBb = 3.01 m/s

Example 4: A 50 g bullet strikes a 1-kg block, passes all the way through, then lodges into the 2 kg block. Afterward, the 1 kg block moves at 1 m/s and the 2 kg block moves at 2 m/s. What was the entrance velocity of the bullet? 1 kg 2 kg vAb= ? 2 kg 1 kg 1 m/s 2 m/s Continued…

mAvAb + mBvBb + mCvCb = mBvBa + (mA+mC) vACa 50 g Find entrance velocity of bullet: mA= 0.05 kg; vAb= ? 2 kg 1 kg 1 m/s 2 m/s Momentum Before = Momentum After mAvAb + mBvBb + mCvCb = mBvBa + (mA+mC) vACa (0.05 kg)vAb =(1 kg)(1 m/s)+(2.05 kg)(2 m/s) (0.05 kg) vAb =(5.1 kg m/s) vAb= 102 m/s