1. Evaluating Expressions and Functions

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Presentation transcript:

1. Evaluating Expressions and Functions Example 1: Evaluate the following expressions when a = -2, b = -5, c = 7 2ab – 3ac + 2abc 2(-2)(-5) – 3(-2)(-5) + 2(-2)(-5)(7) 3a2 – 2b3c 3(-2)^2 – 2(-5)^3(7) │a – b – c + abc │ Abs( -2 – (-5) – 7 + (-2)(-5)(7))

1. Evaluating Expressions and Functions Function Notation f(x) means output when input is x for a given rule f(x) f(x) = h(x) = h(a) = g(x) = h(b) = y = OUTPUT Example 2: Evaluate f(x) when x = 7 f(x) = 2x – 10 f(7) = 2(7) – 10 f(7) = 4

1. Example 3: Evaluate f(-3), for the following functions, f(x), if: Evaluating Expressions and Functions Example 3: Evaluate f(-3), for the following functions, f(x), if: a. f(x) = 2x3 – 2x + 10 f(-3) = 2(-3)3 – 2(-3) + 10 = -38 b. f(x) = 3x(5 – 2x2)(4 + 3x) f(-3) = 3(-3)[5 – 2(-3)2][4 + 3(-3)] f(-3) = -9(-13)(-5) = -585 c. f(x) = │(x – 5)3│ f(-3) =│((-3) – 5)3│= 512

1. Example 3: Evaluate the following functions Evaluating Expressions and Functions Example 3: Evaluate the following functions a. g(a) = 10a2 – 5; g(-5) g(-5) = 10(-5)2 – 5 = 245 b. h(b) = -3b + 15; h(-2.5) h(-2.5) = -3(-2.5) + 15 = 22.5 c. z(x) = │z – 5│- 25; z(5) z(5) = │5 – 5│- 25 = -25

1. Example 4: Evaluate the following functions a. g(a) = a + 5; g(2a) Evaluating Expressions and Functions Example 4: Evaluate the following functions a. g(a) = a + 5; g(2a) g(2a) = (2a) + 5 = 2a + 5 b. h(t) = -3t + 15; h(5t) h(5t) = -3(5t) + 15 h(5t) = -15t + 15 c. z(x) = 2x – 5; z(x – 4) z(x-4) = 2(x – 4) – 5

1. Example 5: Evaluate the following functions Evaluating Expressions and Functions Example 5: Evaluate the following functions a. g(a) = a2 + 5; g(-3a) g(-3a) = (-3a)2 + 5 = 9a2 + 5 b. h(t) = 3t3 + 15; h(t2) h(t2) = 3(t2)3 + 15 = 3t6 + 15 c. z(x) = 2x4 – 5x2; z(4x) z(4x) = 2(4x)4 – 5(4x)2 = 512x4 – 80x2