Objective- To solve problems involving the Pythagorean Theorem.

Slides:



Advertisements
Similar presentations
Objective- To solve problems involving the Pythagorean Theorem.
Advertisements

Jeopardy Review Find the Missing Leg / Hypotenuse Pythagorean Theorem Converse Distance Between 2 Points Everybody’s Favorite Similar T riangles Q $100.
What is the difference between a new penny and an old quarter? Only 4 Gen!uses.
Algebra I by James Wenk © 2003 published by TEACHINGpoint as part of the Expert Systems for Teachers Series 1 3) 180 Rule for Triangles Objective-To find.
The Pythagorean Theorem. The Right Triangle A right triangle is a triangle that contains one right angle. A right angle is 90 o Right Angle.
Lesson 10.1 The Pythagorean Theorem. The side opposite the right angle is called the hypotenuse. The other two sides are called legs. We use ‘a’ and ‘b’
The Pythagorean Theorem. Pythagoras Lived in southern Italy during the sixth century B.C. Lived in southern Italy during the sixth century B.C. Considered.
Objective The student will be able to: use the Pythagorean Theorem Designed by Skip Tyler, Varina High School.
Pythagorean Theorem As posted by: oints/math/pythagorean.html.
Sec 6.6 Pythagorean Theorem. Objective- To solve problems involving the Pythagorean Theorem. For Right Triangles Only! leg hypotenuse - always opposite.
Pythagorean Theorem Mr. Parks Algebra Support. Objective The student will be able to: Find the missing side of a right Triangle using the Pythagorean.
MA.912.G.5.1 : Apply the Pythagorean Theorem and its Converse. A.5 ft B.10 ft C. 15 ft D. 18 ft What is the value of x? x 25 ft 20 ft.
The Pythagorean Theorem. The Parts of a right triangle a b c l egs hypotenuse a² + b² = c².
Learning Target: I can solve problems involving the Pythagorean Theorem. For Right Triangles Only! leg hypotenuse - always opposite the right angle.
Name:__________ warm-up A circular pond has an area of 69.3 square meters. What is the radius of the pond? Round to the nearest tenth of a meter.
Geometry Section 9.2 The Pythagorean Theorem. In a right triangle the two sides that form the right angle are called the legs, while the side opposite.
Objective The student will be able to:
Warm up r = -3 k = -3 x = – 6r = 2r k – 5 = 7k + 7
The Distance Formula & Pythagorean Theorem Day 90 Learning Target : Students can find the distance between 2 points using the distance formula.
Warm up Solve – 6r = 2r k – 5 = 7k (x + 4) = 6x r = -3 k = -3 x = 2.
Do Now: A golf ball is launched at 20 m/s at an angle of 38˚ to the horizontal. 1.What is the vertical component of the velocity? 2.What is the horizontal.
Objective The student will be able to: use the Pythagorean Theorem Designed by Skip Tyler, Varina High School.
Sec 6.6 Pythagorean Theorem (Leg1) 2 + (leg2) 2 = (Hyp) 2 hypotenuse Leg 2 Leg 1.
Pythagorean Theorem. What is a right triangle? It is a triangle which has an angle that is 90 degrees. The two sides that make up the right angle are.
Warm up Solve – 6r = 2r k – 5 = 7k (x + 4) = 6x r = -3 k = -3 x = 2.
Pre-Algebra Q4W1: Pythagorean Theorem Objective: I can apply the Pythagorean Theorem to determine unknown side lengths in right triangles.
The Pythagorean Theorem
The Distance and Midpoint Formulas
SOL 8.10 Pythagorean Theorem.
Objective The student will be able to:
Pythagorean Theorem Converse
Objective The student will be able to:
Pythagorean Theorem What is it??
Lesson 6.2 Square Roots Involving Variables
Objective The student will be able to:
Objective- To solve problems involving the Pythagorean Theorem.
Lesson 3-8 The Pythagorean Theorem
5-3: The Pythagorean Theorem
Pythagorean Theorem.
Pythagorean Theorem.
7.0: Pythagorean Theorem Objectives:
The Pythagorean Theorem
Objective- To solve problems involving the Pythagorean Theorem.
Pythagorean Theorem.
The Distance Formula & Pythagorean Theorem
Warm up r = -3 k = -3 x = – 6r = 2r k – 5 = 7k + 7
Objective - To graph linear equations using x-y charts.
Objective The student will be able to:
Objective- To find the slope of a line given
If a triangle is a RIGHT TRIANGLE, then a2 + b2 = c2.
Pythagorean Theorem, its Converse and the coordinate system
Warm up r = -3 k = -3 x = – 6r = 2r k – 5 = 7k + 7
Objective- To simplify expressions involving rational exponents
Lesson 5.6 Solving Quadratic Equations Using Factoring
Lesson 7.3 Using the Quadratic Formula
Objective - To solve problems involving scientific notation
Objective - To simplify or reduce algebraic fractions.
Objective - To add and subtract algebraic fractions.
Objective The student will be able to:
Objective The student will be able to:
Lesson 6.7 Distance Formula
Objective The student will be able to:
Objective - To write equations of parallel and perpendicular lines.
Lesson 6.3 Operations with Roots - Simplifying Radical Expressions
Objective The student will be able to:
Lesson 1.7 Distributive Property
Objective The student will be able to:
Pythagorean Theorem.
Pythagorean Theorem.
Pythagorean Theorem & Its Converse
Presentation transcript:

Objective- To solve problems involving the Pythagorean Theorem. Lesson 6.6 Pythagorean Theorem Objective- To solve problems involving the Pythagorean Theorem. For Right Triangles Only! hypotenuse - always opposite the right angle leg leg Algebra I by James Wenk © 2003 published by TEACHINGpoint as part of the Expert Systems for Teachers Series Algebra 1 by James Wenk © 2003 published by TEACHINGpoint

Objective- To solve problems involving the Pythagorean Theorem. For Right Triangles Only! hypotenuse c leg a b leg Algebra I by James Wenk © 2003 published by TEACHINGpoint as part of the Expert Systems for Teachers Series

Objective- To solve problems involving the Pythagorean Theorem. For Right Triangles Only! hypotenuse c a b b a Algebra I by James Wenk © 2003 published by TEACHINGpoint as part of the Expert Systems for Teachers Series

Objective- To solve problems involving the Pythagorean Theorem. For Right Triangles Only! Pythagorean Theorem c a b Algebra I by James Wenk © 2003 published by TEACHINGpoint as part of the Expert Systems for Teachers Series

Solve for x. x 6 8 Algebra I by James Wenk © 2003 published by TEACHINGpoint as part of the Expert Systems for Teachers Series

Solve for y. 7 4 y Algebra I by James Wenk © 2003 published by TEACHINGpoint as part of the Expert Systems for Teachers Series

Solve for t. 6 t 15 Algebra I by James Wenk © 2003 published by TEACHINGpoint as part of the Expert Systems for Teachers Series

Pythagorean Triples 3 4 5 6 8 10 9 12 15 12 16 20 Algebra I by James Wenk © 2003 published by TEACHINGpoint as part of the Expert Systems for Teachers Series

Pythagorean Triples 3 4 5 5 12 13 7 24 25 6 8 10 10 24 26 14 48 50 9 12 15 15 36 39 21 72 75 12 16 20 12 9 15 Algebra I by James Wenk © 2003 published by TEACHINGpoint as part of the Expert Systems for Teachers Series

To the nearest tenth of a foot, find the length of the diagonal of a rectangle with a width of 4 feet and a length of 10 feet. x 4 ft. 10 ft. Algebra I by James Wenk © 2003 published by TEACHINGpoint as part of the Expert Systems for Teachers Series

A car drives 20 miles due east and then 45 miles due south. To the nearest hundredth of a mile, how far is the car from its starting point? 20 miles x 45 miles Algebra I by James Wenk © 2003 published by TEACHINGpoint as part of the Expert Systems for Teachers Series

Informal Proof #1 Inscribe a square within the square. Algebra I by James Wenk © 2003 published by TEACHINGpoint as part of the Expert Systems for Teachers Series

Informal Proof #1 a b c a b c c b c a b a Algebra I by James Wenk © 2003 published by TEACHINGpoint as part of the Expert Systems for Teachers Series

Informal Proof #1 a b c a b c a b c c b c a b a Algebra I by James Wenk © 2003 published by TEACHINGpoint as part of the Expert Systems for Teachers Series

Informal Proof #1 a b c b c a c b c a b a Algebra I by James Wenk © 2003 published by TEACHINGpoint as part of the Expert Systems for Teachers Series

Informal Proof #1 a b c b c b c a a c b c a b a Algebra I by James Wenk © 2003 published by TEACHINGpoint as part of the Expert Systems for Teachers Series

Informal Proof #1 a b c b c b c a a c a b Algebra I by James Wenk © 2003 published by TEACHINGpoint as part of the Expert Systems for Teachers Series

Informal Proof #1 a b c b c b c a a b c a c a b Algebra I by James Wenk © 2003 published by TEACHINGpoint as part of the Expert Systems for Teachers Series

Informal Proof #1 a b c c b a b c a c a b Algebra I by James Wenk © 2003 published by TEACHINGpoint as part of the Expert Systems for Teachers Series

Informal Proof #1 a b c c b a b c a c a c a b b Algebra I by James Wenk © 2003 published by TEACHINGpoint as part of the Expert Systems for Teachers Series

Informal Proof #1 a b c c b a b c a c a b Algebra I by James Wenk © 2003 published by TEACHINGpoint as part of the Expert Systems for Teachers Series

Informal Proof #1 a b c c b a b c a c a b Algebra I by James Wenk © 2003 published by TEACHINGpoint as part of the Expert Systems for Teachers Series

Informal Proof #1 a b c a c b b c a b c a c a b Algebra I by James Wenk © 2003 published by TEACHINGpoint as part of the Expert Systems for Teachers Series

Informal Proof #1 a c b b c a c b b a c a c a b Algebra I by James Wenk © 2003 published by TEACHINGpoint as part of the Expert Systems for Teachers Series

Informal Proof #1 a b c c b b a c a c a a c b b Algebra I by James Wenk © 2003 published by TEACHINGpoint as part of the Expert Systems for Teachers Series

Informal Proof #1 a b c c b b a b c a c a a c b Algebra I by James Wenk © 2003 published by TEACHINGpoint as part of the Expert Systems for Teachers Series

Informal Proof #1 a b c c b a b c a a c b Algebra I by James Wenk © 2003 published by TEACHINGpoint as part of the Expert Systems for Teachers Series

Informal Proof #2 - - a + b a b c a b c c b c a b a = = Total Purple Yellow Area Area Area - = a b - c a = b c c b c a b a Algebra I by James Wenk © 2003 published by TEACHINGpoint as part of the Expert Systems for Teachers Series