Proportions and Similar Figures

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Proportions and Similar Figures ALGEBRA 1 LESSON 4-2 10. 12 in. 11. 87.5 mi 12. 145.25 mi 13. 325.5 mi 14. 350 mi 15. a. Lincoln to San Paulo = 16 mi Lincoln to Duncanville = 26 mi San Paulo to Duncanville = 18 mi b. 26 mi roundtrip 16. 1 cm : 8 km 17. 4 in. by 6 in. 18. 2 in. by 4 in. 19. 2 in. by 3 in. pages 192–195  Exercises 1. AB PQ, BC QR, CA RP, A P, B Q, C R 2. ED JH, DF HK, FE KJ, D H, E J, F K 3. 3.125 ft 4. 13.33 cm 5. 80 in. 6. 40 m 7. 20.25 cm 8. 7.2 ft 9. 4.8 ft – 2 3 4-2

Proportions and Similar Figures ALGEBRA 1 LESSON 4-2 20. 3.2 in. by 4.8 in. 21. 33.75 in. 22. 22.5 ft by 27 ft 23. a. Answers may vary. Sample: GK and RQ are not corresponding sides. b. = 24. 1 in. : 12 ft 25. 9 ft by 12 ft 26. 3 ft 27. 216 ft2 28. yes; because it is 6 ft wide and 9 ft long 29. 48 cm long by 20 cm wide 30. a. 6 m b. 6 m, 18 m c. Yes, the ratio of the sides is equal to the ratio of perimeters in similar figures. d. 2 m2, 18 m2 e. Answers may vary. Sample: The area ratio is the square of the side ratio. 31. Answers may vary. Sample: doll house to regular house, model car to real car 32. a. Yes; the sides are proportional. b. The volume ratio is the cube c. 27 : 1 33. a = 8, b = 6, c = 10 GH PQ HL RQ 4-2

Proportions and Similar Figures ALGEBRA 1 LESSON 4-2 34. about 1 in. : 30.5 mi 35. 400,400 km 36. a. = b. 3.2 c. 11.2 in. d. 39.2 in.2 37. B 38. I 39. [2] smaller area: 6 • 5 = 30; 30 ft2; larger area: 10 • 12 = 120; 120 ft2;       = 0.5(120) = 30x      60 = 30x 2 = x Two gallons of paint should cover a 10 ft  20 ft wall. [1] incorrect calculation for one area and proportion solved correctly OR correct area calculations but proportion set up incorrectly 0.5 30 x 120 8 8 + x 5 7 4-2

Proportions and Similar Figures ALGEBRA 1 LESSON 4-2 77.5 16 55 12 40. [4] a.      = 77.5(12) = 16(55)      930 = 880 Since the cross products are not equal, the proportion is not true. So the postcard is not similar to the painting. b. = OR = The postcard should be 12 cm  16.9 cm OR 11.4 cm  16 cm. / [3] appropriate methods, but with one computational error OR found only one possible postcard size [2] incorrect proportions solved correctly [1] correct answer with no work shown 41. 4.5 42. 16 43. –22 44. 40 45. b < –4 46. x ≥ 7 47. m < –4 48. h > – / 2 3 6 7 77.5 x 55 12 77.5 16 55 y 3 2 4-2