Draw a line segment [qr] 8cm in length

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Presentation transcript:

Construct the triangle pqr where |qr|=8cm, |<pqr|=52o and |<prq|=46o (A S A) Draw a line segment [qr] 8cm in length. Name the points and mark the length. At q using a protractor mark and draw an angle of 52o. At r mark and draw an angle of46o Mark the point of intersection of the two angles. This is the point p. p Sketches Quit 52.0 ° 46.0 ° Proofs q |qr|=8cm r Menu END OF CONSTRUCTION

Construct a triangle abc where |ab| = 12cm, |<bac|=65o and |ac| = 9 cm (S A S) USE MOUSE CLICKS TO VIEW CONSTRUCTION Draw a line segment 12cm in length. Name the points and mark the length. Use a protractor to draw a line at 65o to |ab|. Use a compass with a as centre and 9cm radius to draw an arc on this line. Mark the point of intersection c. Join c to b and complete labels. c |ac|=9cm 65.0 ° Sketches Quit a b Proofs Menu |ab|=12cm END OF CONSTRUCTION

Construct the bisector of an angle USE MOUSE CLICKS TO VIEW CONSTRUCTION Draw the angle aob. Using the vertex o as centre draw an arc to meet the arms of the angle at x and y. Using x as centre and the same radius draw a new arc. Using y as centre and the same radius draw an overlapping arc. Mark the point where the arcs meet. The bisector is the line from o to this point. a x x x o Quit Sketches y Menu Proofs b END OF CONSTRUCTION

Construct the perpindicular bisector of a line segment USE MOUSE CLICKS TO VIEW CONSTRUCTION Draw the line segment Using a as centre and a radius greater than half |ab| draw an arc. Using b as centre and the same radius draw another arc. Draw a line through the points where the arcs cross. a b Sketches Quit Proofs Menu END OF CONSTRUCTION

Divide the line segment [ab] into three equal parts USE MOUSE CLICKS TO VIEW CONSTRUCTION Draw the line segment [ab]. Through a draw a line at an acute angle to [ab]. On this line use circle arcs of the same radius to mark off three segments of equal length [ar], [rs] and [st]. Join t to b. Throuth s and r draw line segments parallel to [tb] to meet [ab] at d and c. Now |ac|=|cd|=|db| a c d b r s Quit Sketches t Menu Proofs END OF CONSTRUCTION