Use the distributive rule in arithmetic 5c 3. Algebra and Bidmas Use the distributive rule in arithmetic 5c Use the distributive rule in algebra 5c Use the order of operations 5c Use the order of operations with algebra 5a Work with diagrammatic representations of expressions 6c Apply the order of operations to substitution in simple cases 6c Correctly calculate 2n and n² 6b Use the correct order of operations when substituting in simple whole numbers into algebraic expressions 6a Reference material Text book: section 7.2 MEP: 8.12 Formulae section 1 and 2

When you break 32 x 8 into 30 x 8 + 2 x 8 Distributive law When you break 32 x 8 into 30 x 8 + 2 x 8 In algebra this looks like 3a + 4a = 7a  20 May 2019

Brackets Indices (powers) Division Multiplication Addition Subtraction Substitution – Algebra and bidmas including (2n and n²) calculations are carried out in this order Brackets Indices (powers) Division Multiplication Addition Subtraction so 8 + 4 x 3 = 20 (8 + 12) 3(7 + 2) = 27 4 + 6²÷ 9 = 8 (4 + 36 ÷ 9 = 4 + 4) 35 – (8 – 3) ² = 10 20 May 2019

Substitution – Algebra and bidmas including (2n and n²) Evaluate 4p + 6 when i) p = 5 ii) p = -3 iii) p = 0 p = 5 4p + 6 4 x p + 6 4 x 5 + 6 = 20 + 6 = 26 p = -3 4p + 6 4 x p + 6 4 x -3 + 6 = -12 + 6 = -6 p = 0 4p + 6 4 x p + 6 4 x 0+ 6 = 0 + 6 = 0 20 May 2019

Evaluate 2n – 21 when i) n = 7 ii) n = 12 iii) n = -3 2 x n – 21 2 x 7 – 21 = 14 – 21 = -7 n = 12 2n – 21 2 x n – 21 2 x 12 – 21 = 24 – 21 = 3 n = -3 2n – 21 2 x n – 21 2 x -3 – 21 = -6 – 21 = -27 20 May 2019

Evaluate 2n and n² when i) n = 3 ii) n= 7 iii) n = -4 2n means 2 x n n² means n x n 2n = 2 x n n² = n x n = 2 x 3 = 3 x 3 2n = 6 n² = 9 ii) n = 7 2n means 2 x n n² means n x n 2n = 2 x n n² = n x n = 2 x 7 = 7 x 7 2n = 14 n² = 49 iii) n = -4 2n means 2 x n n² means n x n 2n = 2 x -4 n² = n x n = 2 x -4 = -4 x -4 2n = -8 n² = 16 20 May 2019