Calculating Empirical and Molecular Formulas

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Presentation transcript:

Calculating Empirical and Molecular Formulas

Empirical vs. Molecular Formulas Empirical Formula A formula for a compound that gives the smallest whole-number ratio of each type of atom Molecular Formula A formula for a compound that gives the specific number of each type of atom in a molecule Empirical Formula: HO Molecular Formula: H2O2

Calculating Empirical Formula Example: Suppose we decompose a sample of water in the laboratory and find that it produces 3.0 grams of hydrogen and 24 grams of oxygen. Calculate the empirical formula? 𝑀𝑜𝑙𝑒𝑠 𝐻=3.0 𝑔 𝐻 × 1 𝑚𝑜𝑙 𝐻 1.01 𝑔 𝐻 =3.0 𝑚𝑜𝑙 𝐻 𝑀𝑜𝑙𝑒𝑠 𝑂=24.0 𝑔 𝑂 × 1 𝑚𝑜𝑙 𝑂 16.00 𝑔 𝑂 =1.5 𝑚𝑜𝑙 𝑂 𝐻 3 𝑂 1.5 = 𝐻 2 𝑂

Your Turn A compound contains nitrogen and oxygen is decomposed in the laboratory and produces 24.5 grams of nitrogen and 70.0 grams of oxygen. Calculate the empirical formula of the compound.

Calculating Molecular Formulas Molecular Formula = Empirical formula x n n = 1, 2, 3 … Example: What is the molecular formula for fructose from its empirical formula, CH2O, and its molar mass, 180.2 g/mol. To find n: 𝑛= 𝑀𝑜𝑙𝑎𝑟 𝑀𝑎𝑠𝑠 𝐸𝑚𝑝𝑖𝑟𝑖𝑐𝑎𝑙 𝐹𝑜𝑟𝑚𝑢𝑙𝑎 𝑀𝑜𝑙𝑎𝑟 𝑀𝑎𝑠𝑠 𝑛= 180.2 𝑔/𝑚𝑜𝑙 1 12.01 +2 1.01 +16.00 n = 6 𝐶 𝐻 2 𝑂 𝑥 6= 𝐶 6 𝐻 12 𝑂 6