2-5 Solving Equations with the Variable on Each Side

Slides:

Advertisements

Similar presentations

Identify the number of solutions of an equation

Advertisements

Solving Equations with the Variable on Both Sides Objectives: to solve equations with the variable on both sides.

3-5 Solving Equations with the variable on each side Objective: Students will solve equations with the variable on each side and equations with grouping.

Bkevil Solve Equations With Variables on Both Sides.

Solve an equation with variables on both sides

Solve an equation using subtraction EXAMPLE 1 Solve x + 7 = 4. x + 7 = 4x + 7 = 4 Write original equation. x + 7 – 7 = 4 – 7 Use subtraction property of.

Standardized Test Practice

Step 1: Simplify Both Sides, if possible Distribute Combine like terms Step 2: Move the variable to one side Add or Subtract Like Term Step 3: Solve for.

Standardized Test Practice

Standardized Test Practice

1. solve equations with variables on both sides. 2. solve equations containing grouping symbols. 3.5 Objectives The student will be able to:

Solve Equations with Variables on Both Sides

Warm-Up Warm-Up I will be coming around checking your homework while you are working on your warm-up 1)2(-4 + k) = 24 2)37 = 4x – 6x ) ½(14x – 22)

EXAMPLE 1 Solve an equation with variables on both sides 7 – 8x = 4x – 17 7 – 8x + 8x = 4x – x 7 = 12x – = 12x Write original equation. Add.

1.4 Solving Equations ●A variable is a letter which represents an unknown number. Any letter can be used as a variable. ●An algebraic expression contains.

2.5 Solving equations with variables on both sides

Solving Equations Medina1 Variables on Both Sides.

Solving Equations Medina1 Multi-Step Equations. Steps to solve Medina2 3. Use inverse of addition or subtraction You may not have to do all the steps.

3.2 Solving Equations by Using Addition and Subtraction Addition Property of Equality –If the same number is added to each side of an equation, the resulting.

Practice 2.2 Solving Two Step Equations.

Lesson 1-8 Solving Addition and Subtraction Equations.

Solve an equation using addition EXAMPLE 2 Solve x – 12 = 3. Horizontal format Vertical format x– 12 = 3 Write original equation. x – 12 = 3 Add 12 to.

Example 1 Solving Two-Step Equations SOLUTION a. 12x2x + 5 = Write original equation. 112x2x + – = 15 – Subtract 1 from each side. (Subtraction property.

1. solve equations with variables on both sides. 2. solve equations containing grouping symbols. Objectives The student will be able to:

Use the substitution method

Solve Linear Systems by Substitution January 28, 2014 Pages

1. solve equations with variables on both sides. 2. solve equations with either infinite solutions or no solution Objectives The student will be able to:

Solve Equations With Variables on Both Sides. Steps to Solve Equations with Variables on Both Sides  1) Do distributive property  2) Combine like terms.

Notes 3.4 – SOLVING MULTI-STEP INEQUALITIES

Solving Equations with Variable on Both Sides Objective: Students will solve equations with variables on both sides. Section 3.4.

Solving Equations With Variables on Both Sides Objective: Solve equations with the variable on each side and solve equations involving grouping symbols.

Solving Equations with Variables on Both Sides. Review O Suppose you want to solve -4m m = -3 What would you do as your first step? Explain.

Opener: Find three consecutive odd integers whose sum is -63 Integer #1 = n Integer #2 = n + 2 Integer #3 = n + 4 (n) + (n + 2) + (n + 4) = -63 3n + 6.

Opener (5 + 6) • 2 a + (b + c) + (d • e) 18k x2 + 5x + 4y + 7

3.5 Solving Equations with Variables on Both Sides.

Objectives The student will be able to:

6-3: Solving Equations with variables on both sides of the equal sign

Solving Multistep Equations

Solving Equations with the Variable on Each Side

Lesson 3.5 Solving Equations with the Variable on Both Sides

Linear Equations: Using the Properties Together

Solve for variable 3x = 6 7x = -21

2 Understanding Variables and Solving Equations.

Multi-Step Equations with variable(s) on one side

Objectives The student will be able to:

Objectives The student will be able to:

Do Now 1) t + 3 = – 2 2) 18 – 4v = 42.

Objective Solve equations in one variable that contain variable terms on both sides.

2-4 Solving Multi-Step Equations

Solve an equation by combining like terms

Equations with Variables on Both Sides Day 2

Equations: Multi-Step Examples ..

2 Understanding Variables and Solving Equations.

Equations with Variables on Both Sides

Solving Multi-Step Equations

5x + 3x + 2 = 20 Bellwork #1 of 2 a.) combine the x terms

Warm Up Solve. 1. 2x + 9x – 3x + 8 = –4 = 6x + 22 – 4x 3. + = 5

Using the Addition and Multiplication Principles Together

Objective Solve equations in one variable that contain variable terms on both sides.

Warm Up 9/12/18 Solve x. 1) 3x – 7 = 5 + 2x

Objectives The student will be able to:

Objectives The student will be able to:

Objective 3.4 solve equations with variables on both sides.

Objectives The student will be able to:

Warm-Up 2x + 3 = x + 4.

Algebra 1 Section 2.7.

2-3 Equations With Variables on Both Sides

Objectives The student will be able to:

Objectives The student will be able to:

Solving Equations with Fractions

Presentation transcript:

2-5 Solving Equations with the Variable on Each Side

4 Steps for Solving an Equation 1) Simplify each side of the equation. 2) Get the variables together first. 3) Get the lone numbers together. 4) Get the variable by itself.

Solve: 3x – 7 = 2x + 5 3x – 7 = 2x + 5 x – 7 = 5 Simplify -2x -2x Subtract 2x from both sides to combine the x’s on one side. x – 7 = 5 Simplify +7 +7 Add 7 to both sides to get x by itself. x = 12 Simplify Check: 3(12) – 7 = 2 (12) + 5 36 – 7 = 24 + 5 29 = 29 TRUE

Solve: 4a + 3 = 3a + 5 4a + 3 = 3a + 5 -3a -3a Subtract 3a from both sides a + 3 = 5 Simplify -3 -3 Subtract 3 from both sides a = 2 Simplify Check: 4(2) + 3 = 3(2) + 5 8 + 3 = 6 + 5 11 = 11 TRUE

Solve the following equation. 6x + 5 = 7x – 3 Answer: x = 8

Solve equations with Grouping Symbols 4(2r – 8) = 1/7 (49r + 70) 8r – 32 = 7r + 10 Use Distributive Property -7r -7r Subtract 7r from both sides r – 32 = 10 Simplify +32 +32 Add 32 to both sides r = 42 Simplify Check: 4(2(42) – 8) = 1/7(49(42) + 70) 4(84 – 8) = 1/7(2058 + 70) 4(76) = 1/7(2128) 304 = 304 TRUE

Identity: Equations that are true for all values of the variables. Solve: 4(t + 20) = 1/5(20t + 400) 4t + 80 = 4t + 80 Distribute -4t -4t Subtract 4t 80 = 80 Simplify Does 80 equal 80?? TRUE and the equation is an IDENTITY. Therefore, the answer is ALL NUMBERS

No Solution Equations Solve: 8(5c – 2) = 10(32 + 4c) 40c – 16 = 320 + 40c Distribute -40c -40c Subtract 40c -16 = 320 Simplify Does -16 equal 320?? FALSE Therefore the answer is NO SOLUTION!!

Check Your Progress #4 A purse is on sale for one fourth off the original price, or $12 off. What was the original price of the purse? A. $12 B. $36 C.$48 D. $60 1/4x = 12 x = 48 Answer: C. $48

Homework #14 p. 100 12-44 even, 49-50